PHP将二维数组某一个字段相同的数组合并起来的方法_PHP

本文实例讲述了PHP将二维数组某一个字段相同的数组合并起来的方法。分享给大家供大家参考，具体如下：

例子：

array(3) {
 [0]=>
 array(16) {
  ["id"]=>
  string(2) "42"
  ["uid"]=>
  string(2) "14"
  ["euid"]=>
  string(2) "56"
  ["did"]=>
  string(1) "1"
  ["nid"]=>
  string(1) "0"
  ["phonetime"]=>
  string(10) "1443927600"
  ["createtime"]=>
  string(10) "1443880619"
  ["type"]=>
  string(1) "3"
  ["status"]=>
  string(1) "0"
  ["atype"]=>
  string(1) "1"
  ["mtype"]=>
  string(1) "2"
  ["endtime"]=>
  string(1) "0"
  ["time"]=>
  string(10) "10月04日"
  ["date"]=>
  string(6) "周日"
  ["uname"]=>
  NULL
  ["album"]=>
  string(0) ""
 }
 [1]=>
 array(16) {
  ["id"]=>
  string(2) "40"
  ["uid"]=>
  string(2) "14"
  ["euid"]=>
  string(2) "56"
  ["did"]=>
  string(1) "1"
  ["nid"]=>
  string(1) "0"
  ["phonetime"]=>
  string(10) "1444359600"
  ["createtime"]=>
  string(10) "1444268595"
  ["type"]=>
  string(1) "3"
  ["status"]=>
  string(1) "0"
  ["atype"]=>
  string(1) "1"
  ["mtype"]=>
  string(1) "2"
  ["endtime"]=>
  string(1) "0"
  ["time"]=>
  string(10) "10月09日"
  ["date"]=>
  string(6) "周五"
  ["uname"]=>
  NULL
  ["album"]=>
  string(0) ""
 }
 [2]=>
 array(16) {
  ["id"]=>
  string(2) "43"
  ["uid"]=>
  string(1) "2"
  ["euid"]=>
  string(2) "56"
  ["did"]=>
  string(1) "1"
  ["nid"]=>
  string(1) "0"
  ["phonetime"]=>
  string(10) "1444359620"
  ["createtime"]=>
  string(10) "1444268595"
  ["type"]=>
  string(1) "3"
  ["status"]=>
  string(1) "0"
  ["atype"]=>
  string(1) "1"
  ["mtype"]=>
  string(1) "2"
  ["endtime"]=>
  string(1) "0"
  ["time"]=>
  string(10) "10月09日"
  ["date"]=>
  string(6) "周五"
  ["uname"]=>
  NULL
  ["album"]=>
  string(0) ""
 }
}

现在想要对这个二维数组下的元素，time相同的合并到同一数组下。想要的效果为：

array(2) {
 ["10月04日"]=>
 array(1) {
  [0]=>
  array(16) {
   ["id"]=>
   string(2) "42"
   ["uid"]=>
   string(2) "14"
   ["euid"]=>
   string(2) "56"
   ["did"]=>
   string(1) "1"
   ["nid"]=>
   string(1) "0"
   ["phonetime"]=>
   string(10) "1443927600"
   ["createtime"]=>
   string(10) "1443880619"
   ["type"]=>
   string(1) "3"
   ["status"]=>
   string(1) "0"
   ["atype"]=>
   string(1) "1"
   ["mtype"]=>
   string(1) "2"
   ["endtime"]=>
   string(1) "0"
   ["time"]=>
   string(10) "10月04日"
   ["date"]=>
   string(6) "周日"
   ["uname"]=>
   NULL
   ["album"]=>
   string(0) ""
  }
 }
 ["10月09日"]=>
 array(2) {
  [0]=>
  array(16) {
   ["id"]=>
   string(2) "40"
   ["uid"]=>
   string(2) "14"
   ["euid"]=>
   string(2) "56"
   ["did"]=>
   string(1) "1"
   ["nid"]=>
   string(1) "0"
   ["phonetime"]=>
   string(10) "1444359600"
   ["createtime"]=>
   string(10) "1444268595"
   ["type"]=>
   string(1) "3"
   ["status"]=>
   string(1) "0"
   ["atype"]=>
   string(1) "1"
   ["mtype"]=>
   string(1) "2"
   ["endtime"]=>
   string(1) "0"
   ["time"]=>
   string(10) "10月09日"
   ["date"]=>
   string(6) "周五"
   ["uname"]=>
   NULL
   ["album"]=>
   string(0) ""
  }
  [1]=>
  array(16) {
   ["id"]=>
   string(2) "43"
   ["uid"]=>
   string(1) "2"
   ["euid"]=>
   string(2) "56"
   ["did"]=>
   string(1) "1"
   ["nid"]=>
   string(1) "0"
   ["phonetime"]=>
   string(10) "1444359620"
   ["createtime"]=>
   string(10) "1444268595"
   ["type"]=>
   string(1) "3"
   ["status"]=>
   string(1) "0"
   ["atype"]=>
   string(1) "1"
   ["mtype"]=>
   string(1) "2"
   ["endtime"]=>
   string(1) "0"
   ["time"]=>
   string(10) "10月09日"
   ["date"]=>
   string(6) "周五"
   ["uname"]=>
   NULL
   ["album"]=>
   string(0) ""
  }
 }
}

那么。。。代码很简单，没有想象的那么复杂，想要的结果是个三维数组

$result 为原二维数组

$res = array(); //想要的结果
foreach ($result as $k => $v) {
  $res[$v['time']][] = $v;
}

更多关于PHP相关内容感兴趣的读者可查看本站专题：《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总》

希望本文所述对大家PHP程序设计有所帮助。