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mysql用户自定义函数实例与部分问题解决方法_MySQL

程序员文章站 2022-05-30 21:19:05
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mysql用户自定义函数实例与部分问题解决方法_MySQL

一、查看创建函数的功能是否开启:

mysql> show variables like '%func%';
+-----------------------------------------+-------+
| Variable_name | Value |
+-----------------------------------------+-------+
| log_bin_trust_function_creators | ON |
+-----------------------------------------+-------+
1 row in set (0.02 sec)

二、如果Value处值为OFF,则需将其开启。

mysql> set global log_bin_trust_function_creators=1;
use app02
delimiter //
mysql>DROP FUNCTION IF EXISTS `testhanshu`;

CREATE FUNCTION `testhanshu`(`tustate` int)
RETURNS varchar(2000)
BEGIN

declare oneAddr varchar(200) default '';
declare allAddr varchar(2000) default '';
DECLARE done INT DEFAULT FALSE;

declare curl CURSOR for select utruename from tsys_user where ustate = tustate;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;
open curl;

  REPEAT
FETCH curl INTO oneAddr;
IF NOT done THEN
set oneAddr = CONCAT(oneAddr, ';');
set allAddr = CONCAT(allAddr, oneAddr);
END IF;
UNTIL done END REPEAT;
close curl;
RETURN allAddr;
END;
mysql>select testhanshu(1);

在使用MySql自己定义的函数时,出现错误java.sql.SQLException: This function has none of DETERMINISTIC, NO SQL, or READS SQL DATA in its declaration and binary logging is enabled (you *might* want to use the less safe log_bin_trust_function_creators variable)

解决办法有三种:

1. 登录MySql客户端,执行: SET GLOBAL log_bin_trust_function_creators = 1;
2.在登录MySQL服务器是,在服务启动时加上 “--log-bin-trust-function-creators=1 ”参数并设置为1。
3.在my.ini(my.cnf)中的[mysqld]区段中加上 log-bin-trust-function-creators=1。

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