python3 flask实现文件上传功能
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2022-05-30 20:35:41
本文实例为大家分享了python3-flask文件上传操作的具体代码，供大家参考，具体内容如下
# -*- coding: utf-8 -*-
import o...
本文实例为大家分享了python3-flask文件上传操作的具体代码，供大家参考，具体内容如下
# -*- coding: utf-8 -*-
import os
import uuid
import platform
from flask import flask,request,redirect,url_for
from werkzeug.utils import secure_filename
if platform.system() == "windows":
slash = '\\'
else:
platform.system()=="linux"
slash = '/'
upload_folder = 'upload'
allow_extensions = set(['html', 'htm', 'doc', 'docx', 'mht', 'pdf'])
app = flask(__name__)
app.config['upload_folder'] = upload_folder
#判断文件夹是否存在，如果不存在则创建
if not os.path.exists(upload_folder):
os.makedirs(upload_folder)
else:
pass
# 判断文件后缀是否在列表中
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in allow_extensions
@app.route('/',methods=['get','post'])
def upload_file():
if request.method =='post':
#获取post过来的文件名称，从name=file参数中获取
file = request.files['file']
if file and allowed_file(file.filename):
# secure_filename方法会去掉文件名中的中文
filename = secure_filename(file.filename)
#因为上次的文件可能有重名，因此使用uuid保存文件
file_name = str(uuid.uuid4()) + '.' + filename.rsplit('.', 1)[1]
file.save(os.path.join(app.config['upload_folder'],file_name))
base_path = os.getcwd()
file_path = base_path + slash + app.config['upload_folder'] + slash + file_name
print(file_path)
return redirect(url_for('upload_file',filename = file_name))
return '''
<!doctype html>
<title>upload new file</title>
<h1>upload new file</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=upload>
</form>
'''
if __name__ == "__main__":
app.run(host='0.0.0.0',port=5000)
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持。