发送POST请求在request中有以次data内容

程序员文章站 2022-05-29 17:02:00

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发送POST请求在request中有以下data内容
接口实例：
http://199.199.99.199:8080/cloudTVPlatform/external/api?act=notifyNewDeveloper&PID=CloudTVDN&pversion=1.0&format=JSON
请求方式：POST
请求URL参数说明：
act：操作类型，notifyNewDeveloper，必须
pversion：协议版本，默认为1.0
PID：合作伙伴代码PID，填写CloudTVDN，必须
format：返回的数据格式，支持XML和JSON，默认为JSON
通知数据（POST DATA）实例
POST请求在request中获取参数data内容如下
{
" developerCount ": 2,
"data": [
{
"originalID": "123",
"developerName": "liux",
"developerType": "个人",
"trueName": "刘",
"eMail": "[email protected]",
"phone": "86-10-62565615-208",
"mobile": "86-13900000000",
"fax": "86-10-62565615-208",
"ECURL": "http://DNS/123.JPG",
"CRURL": "",
"CTURL": "",
"registerTime": "2014-04-02 14:14:19"
},
{
"originalID": "124",
"developerName": "liux1",
"developerType": "公司",
"trueName": "百度",
"eMail": "[email protected]",
"phone": "86-10-62565615-208",
"mobile": "86-13900000000",
"fax": "86-10-62565615-208",
"ECURL": "http://DNS/124.JPG",
"CRURL": " http://DNS/125.JPG ",
"CTURL": " http://DNS/126.JPG ",
"registerTime ": "2014-04-02 14:14:19"
}
]
}

返回数据：
返回数据格式：JSON
返回实例：
{
"resultCode": "Success",
"resultMessage": "成功处理"
}
那是客户端提供的接口，而我在服务器端我调用这接口，然后用POST传给他data内容，这应该怎么做啊？我是新手~~~
------解决方案--------------------

引用:

Quote: 引用:

php使用curl扩展模拟post提交。参考代码

/** 
 * Send a POST requst using cURL 
 * @param string $url to request 
 * @param array $post values to send 
 * @param array $options for cURL 
 * @return string 
 */ 
function curl_post($url, array $post = NULL, array $options = array()) 
{ 
    $defaults = array( 
        CURLOPT_POST => 1, 
        CURLOPT_HEADER => 0, 
        CURLOPT_URL => $url, 
        CURLOPT_FRESH_CONNECT => 1, 
        CURLOPT_RETURNTRANSFER => 1, 
        CURLOPT_FORBID_REUSE => 1, 
        CURLOPT_TIMEOUT => 4, 
        CURLOPT_POSTFIELDS => http_build_query($post) 
    ); 

    $ch = curl_init(); 
    curl_setopt_array($ch, ($options + $defaults)); 
    if( ! $result = curl_exec($ch)) 
    { 
        trigger_error(curl_error($ch)); 
    } 
    curl_close($ch); 
    return $result; 
}

然后怎么调用呢？

$data = json_encode(array(你要发送的data数组));
$rs = curl_post("http://199.199.99.199:8080/cloudTVPlatform/external/api?act=notifyNewDeveloper&PID=CloudTVDN&pversion=1.0&format=JSON", $data);

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