用PHP判断oicq是否在线的小程序_PHP教程

来源：keniv

function get_status($uin)
{
$fp = @fsockopen ("infocenter.tencent.com", 80, &$errno, &$errstr, 30);
if(!$fp)
{
return 出错;
}
else
{
fputs($fp, "GET /$uin/l/00/0/ HTTP/1.0 ");
$do = yes;
while(!feof($fp))
{
$line = fgets ($fp,128);
$do = ($do == yes)?yes:(eregi("^GIF89", $line))?yes:no;
if($do == yes)
{
if(ereg("Online", $line))
{
return 在线;
}
elseif(ereg("Offline", $line))
{
return 没在线;
}
}
}
fclose($fp);
}
return 未知;
}
$uin=1697313; //我自己的
echo get_status($uin);
?>

http://www.bkjia.com/PHPjc/532035.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/532035.htmlTechArticle来源：keniv function get_status($uin) { $fp = @fsockopen (infocenter.tencent.com, 80, $errstr, 30); if(!$fp) { return 出错; } else { fputs($fp, GET /$uin/l/00/0/ HTTP/1.0); $d...