欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  后端开发

,php解析带命名空间的xml?

程序员文章站 2022-05-27 10:36:58
...
xml文件有axis生成的:




{"code":"2","message":"企业名称和企业注册号匹配"}





我想获得ns1:checkQyReturn当中的内容。
请问如何用php获取?


回复讨论(解决方案)

可以使用new SimpleXmlElement解决

$x = new SimpleXmlElement($str);  foreach($x->entry as $t){      echo $t->id . "
"; echo $t->updated . "
"; $namespaces = $t->getNameSpaces(true); $gd = $t->children($namespaces['ns1']); echo $gd->phoneNumber; }


参考: http://www.neatstudio.com/show-1549-1.shtml


可以使用new SimpleXmlElement解决

试了命名空间,但解析不了最后用的转换json才解析的。
$xmlstr = preg_replace('/\sxmlns="(.*?)"/', ' _xmlns="${1}"', $simple);
$xmlstr = preg_replace('/ $xmlstr = preg_replace('/(\w+):(\w+)="(.*?)"/', '${1}_${2}="${3}"', $xmlstr);
$xmlobj = simplexml_load_string($xmlstr);

$json = json_decode(json_encode($xmlobj), true);
//print_r(json_decode(json_encode($xmlobj), true));
//print_r($json);
$str = $json['soapenv_Body']['checkQyResponse']['ns1_checkQyReturn'];

暴力一下就简单多了

$s ={{"code":"2","message":"企业名称和企业注册号匹配"}XML;$s = preg_replace('/\w+:/', '', $s);$x = simplexml_load_string($s);print_r($x);
SimpleXMLElement Object(    [@attributes] => Array        (            [soapenv] => //schemas.xmlsoap.org/soap/envelope/            [xsd] => //www.w3.org/2001/XMLSchema            [xsi] => //www.w3.org/2001/XMLSchema-instance        )    [Body] => SimpleXMLElement Object        (            [checkQyResponse] => SimpleXMLElement Object                (                    [checkQyReturn] => {"code":"2","message":"企业名称和企业注册号匹配"}                )        ))