Python实现方便使用的级联进度信息实例

程序员文章站 2022-05-24 18:44:11

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本文实例讲述了Python实现方便使用的级联进度信息的方法。分享给大家供大家参考。具体实现方法如下：

class StepedProgress:
  '''方便显示进度的级联进度信息。
  '''
  def __init__(self, stockPercent=[1], parentProgress=None):
    self.percent = 0
    self.info = ''
    self.subProgress = []
    self.cur_running_process = 0
    self.stockPercent = stockPercent
    self.parentProgress = parentProgress
    # 重新计算进度比，防止初始化时的值加起来不是1
    w = 0.0
    for p in self.stockPercent:
      w += p
    for i in range(0, len(stockPercent)):
      stockPercent[i] = stockPercent[i]/w
    # 初始化子进度
    if len(stockPercent) == 1:
      self.subProgress = None
    else:
      for p in self.stockPercent:
        self.subProgress.append(StepedProgress(parentProgress=self))
  def subprogress(self, index):
    if index >= self.subcount():
      return self.subProgress[self.subcount()-1]
    elif index  self.percent:
      self.percent = percent
    if info is not None:
      self.info = info
    if self.parentProgress is not None:
      self.parentProgress.notifyParentProgress(percent, info)
    else:
      print self.info[:77].ljust(80, '.'), "[%0.1f%%]"%self.percent
if __name__ == "__main__":
  s = StepedProgress([60, 40])
  s.notifyProgress(10, 'aaa')
  s1 = s.subprogress(0)
  s1.notifyProgress(50, 'bbb')
  s3 = s.subprogress(1)
  s3 = StepedProgress([1, 1], parentProgress=s3.parentProgress) #级联子进度
  s3.notifyProgress(20, 'ddd')
  s4 = s3.subprogress(0)
  s4.notifyProgress(50, 'eee')
  s5 = s3.subprogress(1)
  s5.notifyProgress(50, 'fff')

输出结果：

aaa............................................................................. [10.0%]
bbb............................................................................. [30.0%]
ddd............................................................................. [68.0%]
eee............................................................................. [70.0%]
fff............................................................................. [90.0%]

希望本文所述对大家的Python程序设计有所帮助。

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Python实现方便使用的级联进度信息实例