关于单例模式的问题~

name = $name;    }    public static function getInstance(){        if(self::$instance==null){            return new Singleton("");        }        return self::$instance;    }    public function printString(){        echo "hello,this is printString()"."
";    }    public function setName($name){        $this->name = $name;    }    public function getName(){        echo "The name is ".$this->name."
";    }}$class = Singleton::getInstance();$class->printString();$class->setName("jack");$class->getName();$class2 = Singleton::getInstance();$class2->getName();

为何 $class2->getName() 输出的 name 也为空呢？

回复讨论(解决方案)

return new Singleton(""):
应为
self::$instance = new Singleton(""):

如果 return new Singleton(""): 的话就直接返回了另一个实例
就不是单例模式了

name = $name;    }    public static function getInstance(){        if(self::$instance==null){            return new Singleton("");        }        return self::$instance;    }    public function printString(){        echo "hello,this is printString()"."
";    }    public function setName($name){        $this->name = $name;    }    public function getName(){        echo "The name is ".$this->name."
";    }}$class = Singleton::getInstance();$class->printString();$class->setName("jack");$class->getName();$class2 = Singleton::getInstance();$class2->getName();

为何 $class2->getName() 输出的 name 也为空呢？
谢谢楼上~

只要改一处代码即可：你忘了把单例放入$instance

    public static function getInstance(){        if(self::$instance==null){            self::$instance= new Singleton("");        }        return self::$instance;    }