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JS实现简单的二元方程计算器功能示例

程序员文章站 2022-05-23 16:53:17
本文实例讲述了js实现简单的二元方程计算器功能。分享给大家供大家参考,具体如下:

本文实例讲述了js实现简单的二元方程计算器功能。分享给大家供大家参考,具体如下:

<!doctype html public "-//w3c//dtd html 4.0 transitional//en">
<html>
<head>
<title>二元方程</title>
<meta name="author" content="">
<meta name="keywords" content="">
<meta name="description" content="">
</head>
<body>
<script language="javascript">
<!-- begin
var rootparti;
var rootpart;
var det;
var rootparti1;
var rootparti2;
var a;
var b;
var c;
var x1;
var x2;
var i = "i";
function checkquad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
if (a == 0 && c != 0) {
x1 = -c / b;
x2 = "not a quadratic equation, but here is your answer for x";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else if (a == "" && c != 0) {
x1 = -c / b;
x2 = "not a quadratic equation";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else {
quad();
  }
}
function quad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
det = math.pow(b,2) - 4 * a * c;
rootpart = math.sqrt(det) / (2 * a);
rootparti = (math.sqrt(-det) / (2 * a)) + i;
if (parsefloat(rootparti) < 0) {
rootparti1 = rootparti;
rootparti2 = (-1 * parsefloat(rootparti)) + i;
}
else {
rootparti1 = (-1 * parsefloat(rootparti)) + i;
rootparti2 = rootparti;
}
if (rootparti1 == "1i") {
rootparti1 = i;
rootparti2 = "-i";
}
else if (rootparti1 == "-1i") {
rootparti1 = "-i";
rootparti2 = i;
}
if (det == 0) {
x1 = x2 = -b / (2 * a);
}
else if (det > 0) {
x1 = (-b + math.sqrt(det)) / (2 * a);
x2 = (-b - math.sqrt(det)) / (2 * a);
}
else if ((-b / (2 * a)) == 0) {
x1 = rootparti1;
x2 = rootparti2;
}
else {
x1 = (-b / (2 * a) + " + " + rootparti1);
x2 = (-b / (2 * a) + " + " + rootparti2);
}
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
// end -->
</script>
<form name=fquad>
 <table align="center">
  <tr>
<td>
<h2>
<input name=fa size=4>
 <font color="#33ff33">x<sup>2</sup>+</font> 
 <input name=fb size=4>
 <font color="#33ff33"> x +</font> 
 <input name=fc size=4>
 <font color="#33ff33">= 0</font> 
 <input type=button value="求值" onclick="checkquad()">
 <input type=reset value="重填">
</h2>
</td>
</tr>
<tr>
<td>
<h2> <font color="#33ff33">x<sub>1</sub>=</font>
<input name=x1 size=45>
 <font color="#33ff33">x<sub>2</sub>= </font>
<input name=x2 size=45>
</h2>
</td>
</tr>
</table>
</form>
</body>
</html>

ps:这里再为大家推荐几款计算工具供大家进一步参考借鉴:

在线一元函数(方程)求解计算工具:

科学计算器在线使用_高级计算器在线计算:

在线计算器_标准计算器:

更多关于javascript相关内容感兴趣的读者可查看本站专题:《javascript数学运算用法总结》、《javascript数据结构与算法技巧总结》、《javascript数组操作技巧总结》、《javascript排序算法总结》、《javascript遍历算法与技巧总结》、《javascript查找算法技巧总结》及《javascript错误与调试技巧总结

希望本文所述对大家javascript程序设计有所帮助。