欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  后端开发

preg_replace - php中怎么把变量中隐藏的变量解析出来?

程序员文章站 2022-05-23 14:26:17
...
$a = " #0 and #1 or (#0)";
$items = array(
    "a>1",
    "b>0"
);
$str = preg_replace("/#(\w+)/","\$items[$1]",$a);
echo $str;

输出结果: $items[0] and $items[1] or ($items[0])

怎么才能让输出结果是:a>1 and b>0 or (a>1)?
请各位大神帮忙看一下,谢谢!

回复内容:

$a = " #0 and #1 or (#0)";
$items = array(
    "a>1",
    "b>0"
);
$str = preg_replace("/#(\w+)/","\$items[$1]",$a);
echo $str;

输出结果: $items[0] and $items[1] or ($items[0])

怎么才能让输出结果是:a>1 and b>0 or (a>1)?
请各位大神帮忙看一下,谢谢!

正则

$items = [
    'a > 1',
    'b > 0',
    'abc' => 'c > 1'
];
$subject = '#0 and #1 or (#0) and #abc #nooo';
echo preg_replace_callback('/#([a-z0-9_]+)/i', function($v) use ($items){
    return isset($items[$v[1]]) ? $items[$v[1]] : $v[0];
}, $subject);
a > 1 and b > 0 or (a > 1) and c > 1 #nooo
相关标签: php preg_replace