preg_replace - php中怎么把变量中隐藏的变量解析出来?
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2022-05-23 14:26:17
...
$a = " #0 and #1 or (#0)";
$items = array(
"a>1",
"b>0"
);
$str = preg_replace("/#(\w+)/","\$items[$1]",$a);
echo $str;
输出结果: $items[0] and $items[1] or ($items[0])
怎么才能让输出结果是:a>1 and b>0 or (a>1)?
请各位大神帮忙看一下,谢谢!
回复内容:
$a = " #0 and #1 or (#0)";
$items = array(
"a>1",
"b>0"
);
$str = preg_replace("/#(\w+)/","\$items[$1]",$a);
echo $str;
输出结果: $items[0] and $items[1] or ($items[0])
怎么才能让输出结果是:a>1 and b>0 or (a>1)?
请各位大神帮忙看一下,谢谢!
正则
$items = [
'a > 1',
'b > 0',
'abc' => 'c > 1'
];
$subject = '#0 and #1 or (#0) and #abc #nooo';
echo preg_replace_callback('/#([a-z0-9_]+)/i', function($v) use ($items){
return isset($items[$v[1]]) ? $items[$v[1]] : $v[0];
}, $subject);
a > 1 and b > 0 or (a > 1) and c > 1 #nooo
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