求3行3列矩阵a[3][3]={1,2,3,4,5,6,7,8,9}非对角线上元素之和。

#include <stdio.h>
int main()
{	

	int a[3][3]={1,2,3,4,5,6,7,8,9,};
	int b[3];
	int sum=0;
	for (int i = 0; i < 3; i++)
	{
		for (int j = 0; j < 3; j++)
		{
			if(i==j)
			{continue;}
			else
			{sum+=a[i][j];}	
		}
	}
		printf("%d\n",sum);
	return 0;
}