jquery的ajax应用实例

jQuery ajax的前台代码：<script type="text/javascript" src="/include/jquery/jquery-1.1.3.1.pack.js"></script>
<form name="form1" id="form1" action="ajax.php?action=1" method="post">
<input type="hidden" id="comid" name="comid" value="111">
<input type="hidden" id="jobid" name="jobid" value="222">
<input type="hidden" id="userid" name="userid" value="333">
<input type="submit" /></form>
<script language="javascript">
$("#form1").submit
(
function()
{
login();
return false;
}
);
function login()
{
var comid = $("#comid").val();
var jobid = $("#jobid").val();
var userid = $("#userid").val();
$.ajax({
type: "POST",
url: "../include/ajax.php",
data: "action=1" + "&comid=" + comid + "&jobid=" + jobid + "&userid=" + userid,
beforeSend: function(){
},
success: function(msg){
if(msg=="success"){
alert("求职信息，已经提交!请等候通知！")
}else {
alert("信息已发送，请不要重复提交！");
}
}
});
}
</script>PHP的后台代码：<?
header("Cache-Control: no-cache");
require_once("function.php");
switch ($_POST["action"]){
case 1:
$comid=verify_id($_POST["comid"]);
$jobid=verify_id($_POST["jobid"]);
$userid=verify_id($_POST["userid"]);
$appdate=time();
$hasapp=getValue("select * from csj_appjob where jobid=$jobid and userid=$userid and comid=$comid","id");
if($hasapp==""){
$sql="insert into csj_appjob(comid,jobid,userid,appdate) values($comid,$jobid,$userid,$appdate)";
query($sql);
echo "success";
}else{
echo "wrong";
}
break;
default:
break;

}
?>

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