LeetCode(106)Construct Binary Tree from Inorder and Postorder Traversal
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2022-05-20 13:53:02
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Given inorder and postorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
public class Solution {
public TreeNode build(int[]inorder,int instart,int inend,int[] postorder,int poststart,int postend){
if(instart>inend||poststart>postend)
return null;
int val=postorder[postend];
TreeNode root=new TreeNode(val);
int index=0;
for(int i=0;i<=inend;i++){
if(inorder[i]==val){
index=i;
}
}
root.left=build(inorder,instart,index-1,postorder,poststart,poststart+index-instart-1);
root.right=build(inorder,index+1,inend,postorder,poststart+index-instart,postend-1);
return root;
}
public TreeNode buildTree(int[] inorder, int[] postorder) {
if((inorder == null) ||(postorder == null) ||( inorder.length == 0 )|| (postorder.length == 0)) {
return null;
}
return build(inorder,0,inorder.length-1,postorder,0,postorder.length-1);
}
}
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