POJ2255 ZOJ1944 UVA536 Tree Recovery【二叉树遍历】

Tree Recovery

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 16156		Accepted: 9954

Description

Little Valentine liked playing with binary trees very much. Her favorite game was constructing randomly looking binary trees with capital letters in the nodes. 
This is an example of one of her creations: 

                                               D

                                              / \

                                             /   \

                                            B     E

                                           / \     \

                                          /   \     \

                                         A     C     G

                                                    /

                                                   /

                                                  F

To record her trees for future generations, she wrote down two strings for each tree: a preorder traversal (root, left subtree, right subtree) and an inorder traversal (left subtree, root, right subtree). For the tree drawn above the preorder traversal is DBACEGF and the inorder traversal is ABCDEFG. 
She thought that such a pair of strings would give enough information to reconstruct the tree later (but she never tried it). 

Now, years later, looking again at the strings, she realized that reconstructing the trees was indeed possible, but only because she never had used the same letter twice in the same tree. 
However, doing the reconstruction by hand, soon turned out to be tedious. 
So now she asks you to write a program that does the job for her! 

Input

The input will contain one or more test cases. 
Each test case consists of one line containing two strings preord and inord, representing the preorder traversal and inorder traversal of a binary tree. Both strings consist of unique capital letters. (Thus they are not longer than 26 characters.) 
Input is terminated by end of file. 

Output

For each test case, recover Valentine's binary tree and print one line containing the tree's postorder traversal (left subtree, right subtree, root).

Sample Input

DBACEGF ABCDEFG
BCAD CBAD

Sample Output

ACBFGED
CDAB

Source

Ulm Local 1997

问题链接：POJ2255 ZOJ1944 UVA536 Tree Recovery

问题简述：

  根据输入的前序遍历和中序遍历的字符串，求其后序遍历的结果。

问题分析：

  这是一个树的遍历问题，用递归调用实现。

程序说明：（略）

题记：（略）

参考链接：（略）

AC的C++语言程序如下：

/* POJ2255 ZOJ1944 UVA536 Tree Recovery */

#include <iostream>
#include <stdio.h>
#include <string.h>

using namespace std;

const int N = 26;
char s1[N  + 1], s2[N + 1];

void   bulid(int n, char s1[], char s2[])
{
    if(n > 0) {
        int p = strchr(s2, s1[0]) - s2;
        bulid(p, s1 + 1, s2);
        bulid(n - p - 1, s1 + p + 1, s2 + p + 1);
        printf("%c", s1[0]);
    }
}

int main()
{
    while(scanf("%s %s", s1, s2) != EOF) {
        int n = strlen(s1);
        bulid(n, s1, s2);
        printf("\n");
    }

    return 0;
}