pythonr入门学习旅程记录,井字棋小游戏

引言:

刚学python好几天了,从java到python,基础学起来确实比较容易,语法掌握,基本概念上都比较容易入脑,

唯一比较郁闷的是老想着用java的语法去学python代码,这点还需要后面慢慢掌握吧,相信学多种语言的你们也有这种经历吧。

start:开始上代码了,希望有更好的逻辑思维来写,自己也是用最笨拙的思路去写的,如果有可以优化的代码请各位大神指教

#!/user/bin/python
# -*- coding: utf-8 -*-
import os
import sys
#棋盘模块
def model(dictionary,serial=False):
     if serial:
         print('-(初版)井字棋游戏,输入棋号进行对战,')
         print('对应棋号为第一行:a1-a2-a3',end=',')
         print('对应棋号为第二行:b1-b2-b3',end=',')
         print('对应棋号为第三行:c1-c2-c3')
     print(dictionary['a1'] + ' | '+ dictionary['a2'] +' | '+ dictionary['a3'] +' | ')
     print('- +-  +-  +-')
     print(dictionary['b1'] + ' | ' + dictionary['b2'] + ' | ' + dictionary['b3'] + ' | ')
     print('- +-  +-  +-')
     print(dictionary['c1'] + ' | ' + dictionary['c2'] + ' | ' + dictionary['c3'] + ' | ')
#主模块
def main():
    dictionary={'a1':' ','a2':' ','a3':' ','b1':' ','b2':' ','b3':' ','c1':' ','c2':' ','c3':' '}
    model(dictionary, True)
    u1 = 'x' #用户1
    u2 = 'o' #用户2
    stepNumber =1  #记录步数
    break_fang = 0 #获胜者记录
    while(stepNumber<=9):
        fv = True  # 判断条件2
        while fv:
            num = input('请用户u1开始下棋:')
            compare=1 #判断条件1
            for x in dictionary:
                if x.find(num)!=-1:compare=0
            if compare ==0:
                fv=False
        dictionary[num] = u1
        model(dictionary)
        # 0:继续 1,用户1胜,2,用户2胜
        break_fang = forResult(dictionary)
        if break_fang > 0: break
        fv =True #清楚状态
        stepNumber+=1
        while fv:
            num1=input('请用户u2开始下棋:')
            compare = 1  # 判断条件1
            for x in dictionary:
                if x.find(num1)!=-1:compare=0
            if compare == 0:
                fv=False
        dictionary[num1] = u2
        model(dictionary)
        break_fang = forResult(dictionary)
        if break_fang > 0: break
    stepNumber+=1
    gameover(break_fang)
#退出下棋
def gameover(break_fang):
    c = input('是否重新开始? yes:no:')
    if c.find('yes')!=-1:
        main()
    else:
        print('-游戏结束-')
        return
#判断获胜情况
#dictionary:棋盘信息
def forResult(dictionary):
    dicts= dict(dictionary)
    if dicts['a1'] == dicts['a2'] and dicts['a2'] == dicts['a3'] and len(dicts['a3'].strip())>0:
        print('游戏结束,' + '用户1-获胜' if dicts['a1'] == 'x' else '用户2-获胜')
        return 1 if dicts['a1']=='x' else 2
    elif dicts['a1'] == dicts['b2'] and dicts['b2'] == dicts['c3']  and len(dicts['c3'].strip())>0:
        print('游戏结束,' + '用户1-获胜' if dicts['a1'] == 'x' else '用户2-获胜')
        return 1 if dicts['a1'] == 'x' else 2
    elif dicts['a1'] == dicts['b1'] and dicts['b1'] == dicts['c1']  and len(dicts['c1'].strip())>0:
         print('游戏结束,' + '用户1-获胜' if dicts['a1'] == 'x' else '用户2-获胜')
         return 1 if dicts['a1'] == 'x' else 2
    elif dicts['a2'] == dicts['b2'] and dicts['b2'] == dicts['c2']  and len(dicts['c2'].strip())>0:
        print('游戏结束,' + '用户1-获胜' if dicts['a2'] == 'x' else '用户2-获胜')
        return 1 if dicts['a2'] == 'x' else 2
    elif dicts['a3'] == dicts['b3'] and dicts['b3'] == dicts['c3']  and len(dicts['c3'].strip())>0:
         print('游戏结束,' + '用户1-获胜' if dicts['a3'] == 'x' else '用户2-获胜')
         return 1 if dicts['a3'] == 'x' else 2
    elif dicts['a3'] == dicts['b2'] and dicts['b3'] == dicts['c1']  and len(dicts['c1'].strip())>0:
         print('游戏结束,' + '用户1-获胜' if dicts['a3'] == 'x' else '用户2-获胜')
         return 1 if dicts['a3'] == 'x' else 2
    elif dicts['b1'] == dicts['b2'] and dicts['b2'] == dicts['b3']  and len(dicts['b3'].strip())>0:
         print('游戏结束,' + '用户1-获胜' if dicts['b1'] == 'x' else '用户2-获胜')
         return 1 if dicts['b1'] == 'x' else 2
    elif dicts['c1'] == dicts['c2'] and dicts['c2'] == dicts['c3']  and len(dicts['c3'].strip())>0:
         print('游戏结束,' + '用户1-获胜' if dicts['c1'] == 'x' else '用户2-获胜')
         return 1 if dicts['c1'] == 'x' else 2
    else:
        return 0
if __name__ =='__main__':
    main()

 

补一点更改思路:forResult()的另一种实现,compares()函数:少了6行代码量..

def compares(dictionary={'':''},string=''):
    if len(dictionary)>0 | len(string.strip())==0:print('传值为空!')
    else:
        axle =('a1','a3','b2','c1','c3') # 四个角和中间的数特殊判断 条件1
        axle_fang=False #特殊棋号需要多加一种可能性
        for x in axle:
            if string==x:axle_fang=True
        if axle_fang: #条件1
                if dictionary['a1']==dictionary['b2'] and dictionary['b2']==dictionary['c3'] and dictionary['c3'].strip()!=''\
                    or dictionary['a3']==dictionary['b2'] and dictionary['b2']==dictionary['c1']and dictionary['c1'].strip()!='':
                    print('游戏结束,' + '用户1-获胜' if dictionary[string] == 'x' else '用户2-获胜')
                    return 1 if dictionary[string] == 'x' else 2
        # 拆分棋号 splitStr0,splitStr1,普通棋号只需判断俩种a俩种可能,上下-左右间的位置
        splitStr0,splitStr1 = string[0],string[1]
        print(splitStr0+":"+splitStr1)
        if dictionary[splitStr0+'1']==dictionary[splitStr0+'2'] and dictionary[splitStr0+'2']==dictionary[splitStr0+'3']\
            or dictionary['a'+splitStr1]==dictionary['b'+splitStr1] and dictionary['b'+splitStr1]==dictionary['c'+splitStr1]:
            print('游戏结束,' + '用户1-获胜' if dictionary[string] == 'x' else '用户2-获胜')
            return 1 if dictionary[string] == 'x' else 2
        else:return 0

end:写完这些也有九十行代码量了,总感觉太多了...

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