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Python随机生成信用卡卡号的实现方法

程序员文章站 2022-05-19 12:20:13
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本文实例讲述了Python随机生成信用卡卡号的实现方法。分享给大家供大家参考。具体分析如下:

这段Python代码根据信用卡卡号产生规则随机生成信用卡卡号,是可以通过验证的,仅供学习参考,请不要用于非法用途,否则后果自负。

#!/usr/bin/python
"""
gencc: A simple program to generate credit card numbers that pass the
MOD 10 check (Luhn formula).
Usefull for testing e-commerce sites during development.
Copyright 2003-2012 Graham King
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 2 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program; if not, write to the Free Software
Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
"""
# Different naming convention, because translated from PHP
# pylint: disable=C0103
from random import Random
import copy
visaPrefixList = [
    ['4', '5', '3', '9'],
    ['4', '5', '5', '6'],
    ['4', '9', '1', '6'],
    ['4', '5', '3', '2'],
    ['4', '9', '2', '9'],
    ['4', '0', '2', '4', '0', '0', '7', '1'],
    ['4', '4', '8', '6'],
    ['4', '7', '1', '6'],
    ['4']]
mastercardPrefixList = [
    ['5', '1'], ['5', '2'], ['5', '3'], ['5', '4'], ['5', '5']]
amexPrefixList = [['3', '4'], ['3', '7']]
discoverPrefixList = [['6', '0', '1', '1']]
dinersPrefixList = [
    ['3', '0', '0'],
    ['3', '0', '1'],
    ['3', '0', '2'],
    ['3', '0', '3'],
    ['3', '6'],
    ['3', '8']]
enRoutePrefixList = [['2', '0', '1', '4'], ['2', '1', '4', '9']]
jcbPrefixList = [['3', '5']]
voyagerPrefixList = [['8', '6', '9', '9']]
def completed_number(prefix, length):
  """
  'prefix' is the start of the CC number as a string, any number of digits.
  'length' is the length of the CC number to generate. Typically 13 or 16
  """
  ccnumber = prefix
  # generate digits
  while len(ccnumber)  9:
      odd -= 9
    sum += odd
    if pos != (length - 2):
      sum += int(reversedCCnumber[pos + 1])
    pos += 2
  # Calculate check digit
  checkdigit = ((sum / 10 + 1) * 10 - sum) % 10
  ccnumber.append(str(checkdigit))
  return ''.join(ccnumber)
def credit_card_number(rnd, prefixList, length, howMany):
  result = []
  while len(result) 

运行结果如下:

darkcoding credit card generator

Mastercard
----------
5249241445603178
5474662131739768
5581517450441661
5588253309068355
5514774944030079
5122826749528287
5152966434002124
5268127987312292
5385676074198087
5330181839518097

VISA 16 digit
-------------
4539503803848378
4716973052847436
4556149936260376
4486565514724761
4556309354978160
4486560485591158
4916213564870669
4486704671699934
4532839100193192
4486613519985266

VISA 13 digit
-------------
4929905559973
4556870828321
4916868200216
4556189916056
4024007171180

American Express
----------------
376197656730660
342421777432696
342896016604918
343458311286898
374543958196088

Discover
--------
6011676180456692
6011298953567876
6011699666196053

Diners Club / Carte Blanche
---------------------------
30066643308583
38302315481859
38251784096120

enRoute
-------
214935400146170
201435309964331
201450317314858

JCB
---
3506641780149880
3561856856065701
3508395818816022

Voyager
-------
869984254736122
869938197246102
869921075232782

希望本文所述对大家的Python程序设计有所帮助。