Python随机生成信用卡卡号的实现方法
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2022-05-19 12:20:13
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本文实例讲述了Python随机生成信用卡卡号的实现方法。分享给大家供大家参考。具体分析如下:
这段Python代码根据信用卡卡号产生规则随机生成信用卡卡号,是可以通过验证的,仅供学习参考,请不要用于非法用途,否则后果自负。
#!/usr/bin/python """ gencc: A simple program to generate credit card numbers that pass the MOD 10 check (Luhn formula). Usefull for testing e-commerce sites during development. Copyright 2003-2012 Graham King This program is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 2 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program; if not, write to the Free Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA """ # Different naming convention, because translated from PHP # pylint: disable=C0103 from random import Random import copy visaPrefixList = [ ['4', '5', '3', '9'], ['4', '5', '5', '6'], ['4', '9', '1', '6'], ['4', '5', '3', '2'], ['4', '9', '2', '9'], ['4', '0', '2', '4', '0', '0', '7', '1'], ['4', '4', '8', '6'], ['4', '7', '1', '6'], ['4']] mastercardPrefixList = [ ['5', '1'], ['5', '2'], ['5', '3'], ['5', '4'], ['5', '5']] amexPrefixList = [['3', '4'], ['3', '7']] discoverPrefixList = [['6', '0', '1', '1']] dinersPrefixList = [ ['3', '0', '0'], ['3', '0', '1'], ['3', '0', '2'], ['3', '0', '3'], ['3', '6'], ['3', '8']] enRoutePrefixList = [['2', '0', '1', '4'], ['2', '1', '4', '9']] jcbPrefixList = [['3', '5']] voyagerPrefixList = [['8', '6', '9', '9']] def completed_number(prefix, length): """ 'prefix' is the start of the CC number as a string, any number of digits. 'length' is the length of the CC number to generate. Typically 13 or 16 """ ccnumber = prefix # generate digits while len(ccnumber) 9: odd -= 9 sum += odd if pos != (length - 2): sum += int(reversedCCnumber[pos + 1]) pos += 2 # Calculate check digit checkdigit = ((sum / 10 + 1) * 10 - sum) % 10 ccnumber.append(str(checkdigit)) return ''.join(ccnumber) def credit_card_number(rnd, prefixList, length, howMany): result = [] while len(result)运行结果如下:
darkcoding credit card generator Mastercard ---------- 5249241445603178 5474662131739768 5581517450441661 5588253309068355 5514774944030079 5122826749528287 5152966434002124 5268127987312292 5385676074198087 5330181839518097 VISA 16 digit ------------- 4539503803848378 4716973052847436 4556149936260376 4486565514724761 4556309354978160 4486560485591158 4916213564870669 4486704671699934 4532839100193192 4486613519985266 VISA 13 digit ------------- 4929905559973 4556870828321 4916868200216 4556189916056 4024007171180 American Express ---------------- 376197656730660 342421777432696 342896016604918 343458311286898 374543958196088 Discover -------- 6011676180456692 6011298953567876 6011699666196053 Diners Club / Carte Blanche --------------------------- 30066643308583 38302315481859 38251784096120 enRoute ------- 214935400146170 201435309964331 201450317314858 JCB --- 3506641780149880 3561856856065701 3508395818816022 Voyager ------- 869984254736122 869938197246102 869921075232782希望本文所述对大家的Python程序设计有所帮助。
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