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python实现静态服务器

程序员文章站 2022-05-19 11:21:54
本文实例为大家分享了python静态服务器的具体代码,供大家参考,具体内容如下 #coding:utf-8 import socket import mult...

本文实例为大家分享了python静态服务器的具体代码,供大家参考,具体内容如下

#coding:utf-8
import socket
import multiprocessing
import re


html_root_dir = "./html"

class httpserver(object):

  #初始化
  def __init__(self):
    self.serversocket = socket.socket(socket.af_inet, socket.sock_stream)
    self.serversocket.setsockopt(socket.sol_socket, socket.so_reuseaddr, 1)


  #开启服务器启动进程
  def start(self):
    self.serversocket.listen(128)
    while true:
      clintsocket, addree = self.serversocket.accept()
      hanlderprogess = multiprocessing.process(target=self.xiexi, args=(clintsocket,))
      hanlderprogess.start()
      clintsocket.close()

  #绑定端口
  def bind(self,port):
    self.serversocket.bind(("", port))


  #获取请求头,进行解析,同时发送相应头
  def xiexi(clserver):
    date = clserver.recv(1024)
    print date
    list = str(date).split("\r\n")
    # 解析
    requesthead = list[0]
    print requesthead
    #使用正则表达式解析出请求头的文件名称
    file = re.match(r"\w+ +(/[^ ]*) ",requesthead).group(1)

    #对获取的问题名判断,如果是/的就进行显示index.html
    if "/"==file:
      file = "/index.html"
    try:
      f = open(html_root_dir+file,"rb")
    except:
      response_start_line = "http/1.1 200 ok \r\n"
      response_headers = "server:my server\r\n"
      response_body = "the file not file"
    else:
      file_date = f.readline()
      f.close()
      response_start_line = "http/1.1 200 ok \r\n"
      response_headers = "server:my server\r\n"
      response_body = file_date.decode("utf-8")

    response = response_start_line+response_headers+"\r\n"+response_body
    print response
    clserver.send(bytes(response))
    clserver.close()

def main():
  server = httpserver()
  server.bind(1001)
  server.start()

if __name__=="__main__":
  main()

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。