Oracle中检查外键是否有索引的SQL脚本分享
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2022-05-18 23:46:34
复制代码 代码如下:
column columns format a30 word_wrapped
column tablename format a15 word_...
复制代码 代码如下:
column columns format a30 word_wrapped
column tablename format a15 word_wrapped
column constraint_name format a15 word_wrapped
select table_name,
constraint_name,
cname1 || nvl2(cname2, ',' || cname2, null) ||
nvl2(cname3, ',' || cname3, null) ||
nvl2(cname4, ',' || cname4, null) ||
nvl2(cname5, ',' || cname5, null) ||
nvl2(cname6, ',' || cname6, null) ||
nvl2(cname7, ',' || cname7, null) ||
nvl2(cname8, ',' || cname8, null) columns
from (select b.table_name,
b.constraint_name,
max(decode(position, 1, column_name, null)) cname1,
max(decode(position, 2, column_name, null)) cname2,
max(decode(position, 3, column_name, null)) cname3,
max(decode(position, 4, column_name, null)) cname4,
max(decode(position, 5, column_name, null)) cname5,
max(decode(position, 6, column_name, null)) cname6,
max(decode(position, 7, column_name, null)) cname7,
max(decode(position, 8, column_name, null)) cname8,
count(*) col_cnt
from (select substr(table_name, 1, 30) table_name,
substr(constraint_name, 1, 30) constraint_name,
substr(column_name, 1, 30) column_name,
position
from user_cons_columns) a,
user_constraints b
where a.constraint_name = b.constraint_name
and b.constraint_type = 'r'
group by b.table_name, b.constraint_name) cons
where col_cnt > all
(select count(*)
from user_ind_columns i
where i.table_name = cons.table_name
and i.column_name in (cname1, cname2, cname3, cname4, cname5,
cname6, cname7, cname8)
and i.column_position <= cons.col_cnt
group by i.index_name)
/
在上面的基础上修改了一下,可以检查所有的用户。
复制代码 代码如下:
set linesize 400;
column owner format a10 word_wrapped
column columns format a30 word_wrapped
column table_name format a15 word_wrapped
column constraint_name format a40 word_wrapped
select owner,
table_name,
constraint_name,
cname1 || nvl2(cname2, ',' || cname2, null) ||
nvl2(cname3, ',' || cname3, null) ||
nvl2(cname4, ',' || cname4, null) ||
nvl2(cname5, ',' || cname5, null) ||
nvl2(cname6, ',' || cname6, null) ||
nvl2(cname7, ',' || cname7, null) ||
nvl2(cname8, ',' || cname8, null) columns
from (select b.owner,b.table_name,
b.constraint_name,
max(decode(position, 1, column_name, null)) cname1,
max(decode(position, 2, column_name, null)) cname2,
max(decode(position, 3, column_name, null)) cname3,
max(decode(position, 4, column_name, null)) cname4,
max(decode(position, 5, column_name, null)) cname5,
max(decode(position, 6, column_name, null)) cname6,
max(decode(position, 7, column_name, null)) cname7,
max(decode(position, 8, column_name, null)) cname8,
count(*) col_cnt
from (select substr(table_name, 1, 30) table_name,
substr(constraint_name, 1, 30) constraint_name,
substr(column_name, 1, 30) column_name,
position
from dba_cons_columns where owner not in ('sys','system','sysman','hr','oe','exfsys','dbsnmp','mdsys','olapsys','scott','exfsys','sh','pm','ctxsys')) a,
dba_constraints b
where a.constraint_name = b.constraint_name
and b.constraint_type = 'r'
group by b.owner,b.table_name, b.constraint_name) cons
where col_cnt > all
(select count(*)
from dba_ind_columns i
where i.table_name = cons.table_name and i.table_owner=cons.owner
and i.column_name in (cname1, cname2, cname3, cname4, cname5,
cname6, cname7, cname8)
and i.column_position <= cons.col_cnt
group by i.index_name)
/
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