SQL 列不同的表查询结果合并操作
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2022-03-08 09:57:08
两个不同的表进行查询,需要把结果合并,比如table1的列为 id, user_id, type_id,pro_id;table2的列为 id,user_id,collect_id;分别如下图所示ta...
两个不同的表进行查询,需要把结果合并,
比如table1的列为 id, user_id, type_id,pro_id;
table2的列为 id,user_id,collect_id;分别如下图所示
table1:
table2:
将两个表的查询结果合并到一起的查询语句为
select *, null as collect_id from table1 where user_id = 527 union select id,user_id,null as type_id,null as pro_id, collect_id from table2 where user_id = 527;
结果为:
其实就是把对应的列补充到没有该列的表中,在例子中就是把collect_id补充到table1中,
把type_id,pro_id补充到table2中。
补充知识:sql结果集合并用union all 不同表的列合并用join
结果集合并用union all 不同表的列合并用join
select "模块名", "事件编码", "点击数量", "使用时长(单位:分)" from (select t.fun_name as "模块名", t.event_code as "事件编码", sum(click_records) as "点击数量" from (select m.* from default.daily_new_clientrpt_master m where event_id in ( select max(event_id) as "事件" from default.daily_new_clientrpt_master group by user_name,fun_code order by "事件" desc ) ) t where day = today() group by "模块名" ,"事件编码") t5 join ( select t.fun_name as "模块名", t.event_code as "事件编码", round(sum(stay_time)/60000,0) as "使用时长(单位:分)" from (select m.* from default.daily_new_clientrpt_master m where event_id in ( select "事件" from ( select max(event_id) as "事件", max(stay_time) as "事件1" from default.daily_new_clientrpt_master group by user_name,fun_code order by "事件1" desc) ) ) t where day = today() and like(event_code,'%10000') group by "模块名" ,"事件编码" ) t6 on t5."模块名"=t6."模块名" and t5."事件编码"=t6."事件编码"
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