欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  web前端

Codeforces Round #277 (Div. 2)-A. Calculating Function (规律)_html/css_WEB-ITnose

程序员文章站 2022-05-17 11:12:45
...
Calculating Function

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

For a positive integer n let's define a function f:

f(n)?=??-?1?+?2?-?3?+?..?+?(?-?1)nn

Your task is to calculate f(n) for a given integer n.

Input

The single line contains the positive integer n (1?≤?n?≤?1015).

Output

Print f(n) in a single line.

Sample test(s)

input

output

input

output

-3

Note

f(4)?=??-?1?+?2?-?3?+?4?=?2

f(5)?=??-?1?+?2?-?3?+?4?-?5?=??-?3






解题思路:大水题一枚,直接找规律。n%2==0时,f = n/2; 否则,f = -(n+1)/2.





AC代码:

#include #include #include #include #include #include #include #include #include #include #include #include using namespace std;#define INF 0x7fffffffint main(){//    #ifdef sxk//        freopen("in.txt","r",stdin);//    #endif    long long n;    while(scanf("%lld",&n)!=EOF)    {        if(n & 1) printf("%lld\n", -(n+1)/2);        else printf("%lld\n", n/2);    }    return 0;}