PHP异常测试,示例二原创
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2022-05-17 08:20:49
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1) { throw new Exception("Value must be 1 or below"); } return true;}//在 "try" 代码块中触发异常try { checkNum(2); //If the exception is thrown, this text will not be shown echo 'If you see this, the number is 1 or below';}//捕获异常catch (Exception $e) { echo 'Message: ' . $e->getMessage();} * *///---------------------//创建可抛出一个异常的函数,示例二function checkNum($number) { try{ if ($number > 1) { throw new Exception("Value must be 1 or below"); } }catch (Exception $e) { echo 'Message: ' . $e->getMessage(); } return true;}try{ checkNum(2); echo ' If you see this, the number is 1 or below';}catch (Exception $e) { echo 'Error 2 : ' . $e->getMessage();}echo "
It is work good.";
示例一,是网上已有的
示例二,是测试自己的想法的。
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