问个PHP数组合并的问题~请高手指点
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2022-05-16 21:59:35
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$arr1=array( "0"=>array( 'id' => '2', 'b' => 0, 'num' => 4 ), "1"=>array( 'id' => '1', 'b' => 0, 'num' => 4 ) ); $arr2=array( "1"=>array( 'id' => '3', 'b' => 0, 'num' => 4 ), "2"=>array( 'id' => '2', 'b' => 0, 'num' => 4 ) );
想要合并这个两个数组，判断条件，id,b两个元素都相同的情况的NUM值相加。新数组键值重新排列0 1 2 3
求高手指点。谢谢。
回复讨论(解决方案)
array_merge($fruits, $numbered); 合并数组就行了啊
array_merge($fruits, $numbered); 合并数组就行了啊
大哥注意看条件
判断条件，id,b两个元素都相同的情况的NUM值相加。
有人在吗？
$arr1=array( "0"=>array( 'id' => '2', 'b' => 0, 'num' => 4 ), "1"=>array( 'id' => '1', 'b' => 0, 'num' => 4 ) ); $arr2=array( "1"=>array( 'id' => '3', 'b' => 0, 'num' => 4 ), "2"=>array( 'id' => '2', 'b' => 0, 'num' => 4 ) );foreach($arr1 as $v) $res["$v[id]_$v[b]"] = $v;foreach($arr2 as $v) if(isset($res["$v[id]_$v[b]"])) $res["$v[id]_$v[b]"]['num'] += $v['num']; else $res["$v[id]_$v[b]"] = $v;print_r(array_values($res));
Array( [0] => Array ( [id] => 2 [b] => 0 [num] => 8 ) [1] => Array ( [id] => 1 [b] => 0 [num] => 4 ) [2] => Array ( [id] => 3 [b] => 0 [num] => 4 ))
$arr1=array( "0"=>array( 'id' => '2', 'b' => 0, 'num' => 4 ), "1"=>array( 'id' => '1', 'b' => 0, 'num' => 4 ) ); $arr2=array( "1"=>array( 'id' => '3', 'b' => 0, 'num' => 4 ), "2"=>array( 'id' => '2', 'b' => 0, 'num' => 4 ) );foreach($arr1 as $v) $res["$v[id]_$v[b]"] = $v;foreach($arr2 as $v) if(isset($res["$v[id]_$v[b]"])) $res["$v[id]_$v[b]"]['num'] += $v['num']; else $res["$v[id]_$v[b]"] = $v;print_r(array_values($res));
Array( [0] => Array ( [id] => 2 [b] => 0 [num] => 8 ) [1] => Array ( [id] => 1 [b] => 0 [num] => 4 ) [2] => Array ( [id] => 3 [b] => 0 [num] => 4 ))
非常感谢，看了以后思路又开阔了不少，收获良多，再次谢谢大神解答。