欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  后端开发

python pycurl验证basic和digest认证的方法

程序员文章站 2022-05-16 17:44:03
...
这篇文章主要介绍了python pycurl验证basic和digest认证的方法,现在分享给大家,也给大家做个参考。一起过来看看吧

简介

pycurl类似于Python的urllib,但是pycurl是对libcurl的封装,速度更快。

本文使用的是pycurl 7.43.0.1版本。

Apache下配置Basic认证

生成basic密码文件

htpasswd -bc passwd.basic test 123456

开启mod_auth_basic

LoadModule auth_basic_module modules/mod_auth_basic.so

配置到具体目录

<Directory "D:/test/basic">
  AuthName "Basic Auth Dir"
  AuthType Basic
  AuthUserFile conf/passwd.basic
  require valid-user
</Directory>

重启Apache

Apache下配置Digest认证

生成Digest密码文件

htdigest -c passwd.digest "Digest Encrypt" test

开启mod_auth_digest

LoadModule auth_digest_module modules/mod_auth_digest.so

配置到具体目录

<Directory "D:/test/digest">
  AuthType Digest
  AuthName "Digest Encrypt" # 要与密码的域一致
  AuthDigestProvider file
  AuthUserFile conf/passwd.digest
  require valid-user
</Directory>

重启Apache

验证Basic认证

# -*- coding: utf-8 -*-
import pycurl
try:
  from io import BytesIO
except ImportError:
  from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/basic/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_BASIC)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()

验证Digest认证

# -*- coding: utf-8 -*-
import pycurl
try:
  from io import BytesIO
except ImportError:
  from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/digest/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_DIGEST)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()


以上就是python pycurl验证basic和digest认证的方法的详细内容,更多请关注其它相关文章!