欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  IT编程

ASP.Net应用递归算法案例

程序员文章站 2022-05-15 23:46:33
案例需求:动态将一个公司各个部门按照部门顺序排列,在页面动态生成列表,并且子级部门需要比父级部门缩进20px。   页面代码:   :butto...

案例需求:动态将一个公司各个部门按照部门顺序排列,在页面动态生成列表,并且子级部门需要比父级部门缩进20px。

 

页面代码:

 


:button id="btncreate" onclick="btncreate_click" runat="server" text="生成">


后台代码:

 

1、

 

    public class department
    {
        public department(int id, string name, int parentid)
        {
            this.id = id;
            this.name = name;
            this.parentid = parentid;
        }
        public int id { get; set; }
        public string name { get; set; }
        public int parentid { get; set; }
    
    }

2、

 

 

        list listtc = new list();
        public void loaddata()
        {
            listtc.add(new department(1, "财务部", 2));
            listtc.add(new department(2, "公司总部", 0));
            listtc.add(new department(3, "财务组1", 1));
            listtc.add(new department(4, "财务组2", 1));
            listtc.add(new department(5, "研发部", 2));
            listtc.add(new department(6, "研发组1", 5));
            listtc.add(new department(7, "研发组2", 5));
            listtc.add(new department(8, "研发组3", 5));
            listtc.add(new department(9, "业务部", 2));
            listtc.add(new department(10, "业务组1", 9));
            listtc.add(new department(11, "业务组2", 9));
            listtc.add(new department(12, "业务组3", 9));
            listtc.add(new department(13,"研发组1第一小组",6));
            listtc.add(new department(14, "业务组1第一小组", 10));
            listtc.add(new department(15, "研发组1第二小组", 6));
            listtc.add(new department(16, "研发组1第二小组1", 15));
            listtc.add(new department(17, "研发组1第二小组2", 15));
        }

3、

 

 

        list templist = new list();
        public list sort(int parentid)
        {
            var tclist = getlisttc(parentid);
            if (templist.count < listtc.count)
            {
                if (tclist.count > 0)
                {
                    foreach (var tc in tclist)
                    {
                        if (!templist.contains(tc))
                        {
                            templist.add(tc);
                            return sort(tc.id);
                        }
                    }
                    var t = gettc(parentid);
                    return sort(t.parentid);
                }
                else
                {
                    var tc = gettc(parentid);
                    return sort(tc.parentid);
                }
            }
            else
            { 
                return templist;
            }
        }

4、

 

 

       public int getlevel(department tc,int level)
        {
            var t = listtc.find(o => o.id == tc.parentid);
            if (t!=null)
            {
                level++;
                return getlevel(t,level);
            }
            return level;
        }
        public list getlisttc(int parentid)
        {
             var list = listtc.findall(o =>o.parentid == parentid);
             return list;   
        }
        public department gettc(int id)
        {
            var tc = listtc.find(o => o.id == id);
            return tc;
        }
        public string inithtml(int level, string name)
        {
            string html = string.empty;
            html += " 

5、
      public string createhtml()
        {
            var list = sort(0);
       
            string strhtml = string.empty;
            foreach (var tc in list)
            {
                int lev = getlevel(tc, 0);
                strhtml += inithtml(lev, tc.name);
            }
            return strhtml;
        }

6、

 

 

       protected void btncreate_click(object sender, eventargs e)
        {
            loaddata();
            this.literal1.text = createhtml();
        }


 

思路:先将数据排序好,根据当前单位的级别数生成li.

页面效果图:

ASP.Net应用递归算法案例