C++ - 判断文件夹(folder)是否存在(exist)
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2022-05-09 23:50:30
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判断文件夹(folder)是否存在(exit)
本文地址: http://blog.csdn.net/caroline_wendy/article/details/21734915
写入程序, 需要在文件夹中写入数据, 如果文件夹不存在, 则无法写入, 在程序入口需要判断;
由于属于系统层, Windows的两种解决方法.
参考: http://*.com/questions/8233842/how-to-check-if-directory-exist-using-c-and-winapi
1. GetFileAttributesA()函数
DWORD d = GetFileAttributesA(const char* filename); #include <windows.h>
windows系统函数, 判断文件夹是否存在;
代码:
#include <iostream>
#include <string>
#include <windows.h>
using namespace std;
bool dirExists(const std::string& dirName_in)
{
DWORD ftyp = GetFileAttributesA(dirName_in.c_str());
if (ftyp == INVALID_FILE_ATTRIBUTES)
return false; //something is wrong with your path!
if (ftyp & FILE_ATTRIBUTE_DIRECTORY)
return true; // this is a directory!
return false; // this is not a directory!
}
int main(void)
{
std::string folder("./Test");
if (dirExists(folder)) {
std::cout << "Folder : " << folder << " exist!" << std::endl;
} else {
std::cout << "Folder : " << folder << " doesn't exist!" << std::endl;
}
std::string nofolder("./TestNo");
if (dirExists(nofolder)) {
std::cout << "Folder : " << nofolder << " exist!" << std::endl;
} else {
std::cout << "Folder : " << nofolder << " doesn't exist!" << std::endl;
}
return 0;
}
2. _access()函数
int access(const char *filename, int mode); #include <io.h>
mode设为0, 判断文件是否存在; 返回0, 文件存在;
代码:
#include <iostream>
#include <string>
#include <io.h>
using namespace std;
bool dirExists(const std::string& dirName_in)
{
int ftyp = _access(dirName_in.c_str(), 0);
if (0 == ftyp)
return true; // this is a directory!
else
return false; // this is not a directory!
}
int main(void)
{
std::string folder("./Test");
if (dirExists(folder)) {
std::cout << "Folder : " << folder << " exist!" << std::endl;
} else {
std::cout << "Folder : " << folder << " doesn't exist!" << std::endl;
}
std::string nofolder("./TestNo");
if (dirExists(nofolder)) {
std::cout << "Folder : " << nofolder << " exist!" << std::endl;
} else {
std::cout << "Folder : " << nofolder << " doesn't exist!" << std::endl;
}
return 0;
}
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作者:SpikeKing
来源:CSDN
原文:https://blog.csdn.net/caroline_wendy/article/details/21734915
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