/*
用法一:
用str替换指定字符串从起始位置pos开始 长度为为len的字符串
string &replace(size_t pos, size_t len, const string& str)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] a test string!";
s=s.replace(s.find("@"),1,"");
cout<<s<<endl;
}
//this is a test string!
/*
用法二:
用str替换 迭代器 起始位置 和 结束位置的字符串
string &replace(const_iterator i1, const_iterator i2, const string& str)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] [email protected] test string!";
s=s.replace(s.begin(),s.begin()+6,"");
cout<<s<<endl;
}
//[email protected] [email protected] test string!
/*
用法三:
用substr的指定子串(给定起始位置和长度)替换从指定位置上的字符串
string &replace(size_t pos, size_t len, const string& str, size_t subpos, size_t sublen)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] [email protected] test string!";
string str="12345";
s=s.replace(0,5,str,str.find("1"),3); //用str的指定子串（从1位置数共3个字符）替换从0到5位置上的s
cout<<s<<endl;
}
//[email protected] [email protected] test string!
/*
用法四:**string转char*时编译器可能会报出警告,不建议这样做**
用str替换从指定位置0开始长度为5的字符串
string &replace(size_t pos, size_t len, const char*s)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] [email protected] test string!";
char* str="12345";
s=s.replace(0,5,str); //用str替换从指定位置0开始长度为5的字符串
cout<<s<<endl;
}
//[email protected] [email protected] test string!
/*
用法五:**string转char*时编译器可能会报出警告,不建议这样做**
用str替换从指定迭代器位置的字符串
string &replace(const_iterator i1, const_iterator i2, const char* s)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] [email protected] test string!";
char* str="12345";
s=s.replace(s.begin(),s.begin()+9,str); //用str替换从指定迭代器位置的字符串
cout<<s<<endl;
}
//[email protected] test string!
/*
用法六:**string转char*时编译器可能会报出警告,不建议这样做**
用s的前n个字符替换从开始位置pos长度为len的字符串
string& replace(size_t pos, size_t len, const char* s, size_t n)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] [email protected] test string!";
char* str="12345";
s=s.replace(0,9,str,4); //用str的前4个字符替换从0位置开始长度为9的字符串
cout<<s<<endl;
}
//[email protected] test string!
/*用法七：string转char*时编译器可能会报出警告，不建议这样做
用s的前n个字符替换指定迭代器位置(从i1到i2)的字符串
string& replace (const_iterator i1, const_iterator i2, const char* s, size_t n);
*/
int main()
{
string line = "[email protected] [email protected] a test string!";
char* str = "12345";
line = line.replace(line.begin(), line.begin()+9, str, 4); //用str的前4个字符替换指定迭代器位置的字符串
cout << line << endl;
return 0;
}
/*
用法八:用重复n次的c字符替换从指定位置pos长度为len的内容
string &replace(size_t pos, size_t len, size_t, char c)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] [email protected] test string!";
char c='z';
s=s.replace(0,9,3,c); //用重复3次的c字符替换从指定位置0长度为9的内容
cout<<s<<endl;
}
//[email protected] test string!
/*
用法九:用重复n次的c字符替换从指定迭代器位置的内容
string &replace(const_iterator i1, const_iterator i2, size_t, char c)
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const double eps = 1e-7;
const int maxn = 5e5 + 5;
const double pi = acos(-1.0);
int main()
{
string s="this [email protected] [email protected] test string!";
char c='z';
s=s.replace(s.begin(),s.begin()+9,3,c); //用重复3次的c字符替换从指定位置0长度为9的内容
cout<<s<<endl;
}
//[email protected] test string!