Java面试题2

Question：
现有两个数组 A{“a1”,“a2”,“a3”…}、B{“b1”,“b2”,“b3”…}；
按照a1,a2,b1,a3,a4,b2…的序列，返回一个***给定的长度n***的数组

/**
 * @author BadCode
 * @date 2019/9/28  22:07
 */
public class Demo {
    public static void main(String[] args) {
        String[] str1 = {"a1","a2","a3","a4","a5","a6","a7","a8","a9","a10"};
        String[] str2 = {"b1","b2","b3","b4","b5","b6","b7","b8","b9","b10"};
        String[] str3 = new String[str1.length + str2.length];
        method1(str1, str2, str3);
        for (String s : str3) {
            System.out.print(s + " ");
        }
    }

    private static void method1(String[] str1, String[] str2, String[] str3) {
        int count1= 0;
        int count2= 0;
        for (int i = 0; i < str3.length; i++) {
            if ((i + 1) % 3 != 0){
                if (count1 >= str1.length){
                    str3[i] = str2[count2];
                    count2++;
                    continue;
                }
                str3[i] = str1[count1];
                count1++;
            }else {
                if (count2 >= str2.length){
                    str3[i] = str1[count1];
                    count1++;
                    continue;
                }
                str3[i] = str2[count2];
                count2++;
            }
        }
    }
}

打印结果

//method1运行结果
a1 a2 b1 a3 a4 b2 a5 a6 b3 a7 a8 b4 a9 a10 b5 b6 b7 b8 b9 b10 

本博客是本人面试时遇到的问题，仅用来记录，欢迎前辈提出其中的错误或更好的建议。