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如何保证线程的执行顺序

程序员文章站 2022-05-05 21:46:29
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如题,如何保证线程的执行顺序?

1
2
Thread1
Thread2
Thread3

方案一

public class ThreadOrder {

    static Thread thread1 = new Thread(new Runnable() {
        @Override
        public void run() {
            System.out.println("thread1");
        }
    });

    static Thread thread2 = new Thread(new Runnable() {
        @Override
        public void run() {
            System.out.println("thread2");
        }
    });

    static Thread thread3 = new Thread(new Runnable() {
        @Override
        public void run() {
            System.out.println("thread3");
        }
    });

    public static void main(String[] args) throws InterruptedException {
        thread1.start();
        // join()方法,让主线程阻塞
        thread1.join();
        thread2.start();
        thread2.join();
        thread3.start();
        thread3.join();
    }
}
java.lang.Thread#join(long)的实现
public final void join() throws InterruptedException {
        join(0); // 这里时间设置为0毫秒
    }
public final synchronized void join(long millis)
    throws InterruptedException {
        long base = System.currentTimeMillis();
        long now = 0;

        if (millis < 0) {
            throw new IllegalArgumentException("timeout value is negative");
        }

        if (millis == 0) {
            while (isAlive()) {
                wait(0);
            }
        } else {
            while (isAlive()) {
                long delay = millis - now;
                if (delay <= 0) {
                    break;
                }
                wait(delay);
                now = System.currentTimeMillis() - base;
            }
        }
    }

方案二

public class ThreadOrder {
     ...
     // 利用只有一个线程的线程池,按顺序执行thread1 -> thread2 -> thread3
    static ExecutorService executorService = Executors.newSingleThreadExecutor();
    public static void main(String[] args) throws InterruptedException {
        executorService.submit(thread1); // 1、执行thread1
        executorService.submit(thread2); // 2、执行thread2
        executorService.submit(thread3); // 3、执行thread3
        executorService.shutdown();
    }
}
执行结果:
如何保证线程的执行顺序
勘误或支持:由于水平有限,编写时间仓促,文中难免会出现一些错误或者不准确的地方,恳请读者批评指正。有任何的意见或建议,可在评论区留言,共同讨论。