对python实现模板生成脚本的方法详解

最近项目需要，针对主项目提取一个小的基础版本，供于在新建项目时使用，所以就有这个python模板生成脚本，其作用如下：

1、通过配置文件来控制模板中的数据、格式化的过滤条件

2、执行后会把目录下所有的文件都会执行一篇

#!/usr/bin/python
#encoding: utf-8
 
import json
import codecs
import os
 
def get_files(root_path):
  for dir in os.walk(root_path):
    if dir[2]:
      for nf in dir[2]:
        yield os.path.join(dir[0], nf)
 
def exclude_filter(exclude, nfile):
  files_path = exclude.get('file_path')
  files_name = exclude.get('file_name')
  base_name = os.path.basename(nfile)
  exts_name = exclude.get('ext_name')
  base_ext_name = base_name.rsplit(".", 1)[1]
  if files_path:
    for npath in files_path:
      if npath==nfile:
        return true
  elif files_name:
    for name in files_name:
      print name, base_name
      if name==base_name:
        return true
  elif exts_name:
    for name in exts_name:
      print name, base_ext_name
      if name==base_ext_name:
        return true
 
def include_filter(include, nfile):
  files_path = include.get('file_path')
  files_name = include.get('file_name')
  base_name = os.path.basename(nfile)
  if files_path:
    for npath in files_path:
      if npath==nfile:
        return true
  elif files_name:
    for name in files_name:
      if name==base_name:
        return true
 
def main():
  # read config
  config = {}
  with codecs.open("config.json","rb","utf-8") as f:
    config = json.loads(f.read())
  if not config:
    return
 
  template = config.get("template")
  if template and template.get('path'):
    root_path = template.get('path')
    if not os.path.exists(root_path):
      print "source path not exist"
      return
    root_path = os.path.abspath(root_path)
    old_path = os.path.dirname(root_path)
  else:
    return
  exclude = template.get('exclude')
  include = template.get('include')
 
  store = config.get("store")
  if not store or not os.path.exists(store.get('dir_path', '')):
    return
 
  data = config.get("data")
  if not data:
    return
 
  if not os.path.exists(root_path):
    print 'root path not exists'
    return
 
  if os.path.isfile(root_path):
    files = [root_path]
  else:
    base_name = os.path.basename(root_path)
    store_root_path = os.path.join(store.get('dir_path'), base_name)
    if not os.path.exists(store_root_path):
      os.mkdir(store_root_path)
    files = get_files(root_path)
 
  for nfile in files:
    print nfile
    try:
      with codecs.open(nfile, "rb", "utf-8") as f:
        s = f.read()
 
      if not exclude_filter(exclude, nfile) or include_filter(include, nfile):
        s = s % data
    except:
      with codecs.open(nfile, "rb") as f:
        s = f.read()
 
    # save to file
    fn = nfile.replace(old_path, store.get('dir_path'))
    fn_dir = os.path.dirname(fn)
    if not os.path.exists(fn_dir):
      os.makedirs(fn_dir)
    try:
      with codecs.open(fn, "wb", "utf-8") as f:
        f.write(s)
        f.flush()
    except:
      with codecs.open(fn, "wb") as f:
        f.write(s)
        f.flush()
 
if __name__ == '__main__':
  main()

配置文件：

{
 "template": {
  "path" : "d:/tunicorn-web/framework-template",  ##模板文件主目录
  "exclude" : {                  ##不进行模板格式化的文件
   "file_path" : [],  
   "file_name" : ["config.json", "make_project.py"], 
   "ext_name" : ["css", "woff2"],
   "file_type" : [],
   "regex" : []
  },
  "include" : {                  ##进行模板格式化的文件
   "file_path" : [],
   "file_name" : []
  }
 },
 "store":{
  "dir_path" : "e:/test"             ##输出路径主目录     
  "data" : {
  "project_name":"newjava",            ##模板数据
  "project_prefix":"newjava"           ##模板数据
 }
}

执行操作：

1、安装了python环境

2、双击python脚本

3、然后在执行下readme中的步骤

readme：

readme
=============

脚本使用
-------------
1. 打开config.json文件
2. 配置相关信息[输出目录、项目名称、项目前缀]
3. 执行make_project.py脚本
4. 查看输出目录

以上这篇对python实现模板生成脚本的方法详解就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持。