约瑟夫环

PTA 题组一:8-4

代码:

#include <stdio.h>
#define MAXN 20

void CountOff( int n, int m, int out[] );

int main()
{
    int out[MAXN], n, m;
    int i;

    scanf("%d %d", &n, &m);
    CountOff( n, m, out );   
    for ( i = 0; i < n; i++ )
        printf("%d ", out[i]);
    printf("\n");

    return 0;
}

/* 你的代码将被嵌在这里 */
#include <string.h>
void CountOff( int n, int m, int out[] )
{
    int go[n];      //判断是否走了,走了为1,没走为0
    memset(go,0,sizeof(go));
    int cnt = 0;    //当前人报的数
    int goCnt = 1;  //记录走了几个
    int i = 0;      //人数编号循环
    while (1)
    {
        if (go[i] == 0)
        {
            cnt++;
        here:if (cnt == m && go[i] == 0)    //报了指定的数字,并且还没有走
            {
                out[i] = goCnt;
                goCnt++;
                cnt = 0;
                go[i] = 1;
            }
            else if (go[i] == 1)    //已经走了,则继续下一个人判断
            {
                i++;
                goto here;
            }
            
        }
        if (goCnt == n+1)   //如果总共走的超过总人数,结束循环
        {
            break;
        }

        i++;        //人数编号+1,如果超出了总共的人数,编号会到第一个人,即编号下标为0
        if (i == n)
        {
            i = 0;
        }
    }
    
}

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例题2:

代码:

代码思路:yyt

#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
#include <math.h>
int main()
{
    int n,m;
    scanf("%d %d", &n, &m);

    //把人的编号由1到n排好
    int man[n];
    for (int i = 0; i < n; i++)
    {
        man[i] = i+1;
    }

    int putOut[n];  //用于输出的数组
    int go = 0;     //走了几个人
    int num = 1;    //报的数

    while (go < n)
    {
        for (int i = 0; i < n; i++)
        {
            if(*(man+i) != -1)
            {
                if (num == m)
                {
                    putOut[go] = *(man+i);
                    go++;
                    num = 0;
                    *(man+i) = -1;
                }
                num++;
            }
        }
    }
    
    for (int i = 0; i < n; i++)
    {
        printf("%d ",putOut[i]);
    }
    
    return 0;
}