CCPC2019江西省赛-Problem G.Traffic

题目描述：

　　/*纯手打题面*/
　　avin is observing the cars at a crossroads.he finds that there are n cars running in the east-west direction
with the i-th car passing the intersection at time a[i].there are another m cars running in the north-south
direction with the i-th car passing the intersection at time b[i].if two cars passing the intersections at 
the same time,a traffic crash occurs.in order to achieve world peace and harmony,all the cars running in the 
north-south direction wait the same time amount of integral time so that no two cars bump.you are asked the 
minimum waiting time.
/*纯手打题面*/

input

n m
a[i]
b[i]
(1<=n,m<=1000;1<=ai,bi<=1000)

output

the minimum waiting time(integer).

题解心得：

啊啊啊啊啊啊啊啊啊啊啊啊，当时在比赛的时候翻了好久词典，终于把这个题目的意思大概搞懂了

然后和我们队的大佬讨论了好久

一开始爆搜o(n³)

然后想了好久奇奇怪怪的方法，分治什么的，然后就剪枝优化。

但是最后用标记法把时间复杂度压到了o(n²)。

大致思路：

枚举时间（一个循环）

在每个循环里标记a[i]所占的时间点（布尔数组c）

同时标记b[i]+t的时间点（布尔数组d）

接着c&&d;

就可以了。

这题真的水，不加剪枝也能ac。

代码：

以后附。