C语言实现【扫雷小游戏】

 扫雷小游戏我们大家都玩过，这次，自己写了一个简单版本的扫雷游戏。代码如下：

头文件game.h

#ifndef __GAME_H__
#define __GAME_H__

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

#define ROW 9
#define COL 9

#define ROWS ROW+2
#define COLS COL+2

#define EASY_COUNT 10
//#define MIDDLE_COUNT 10   中等难度
//#define HARD_COUNT 10  高级难度


void InitBoard(char a[ROWS][COLS],int rows, int cols,char set); 
void DisplayBoard(char a[ROWS][COLS], int row, int col);
void SetMine(char a[ROW][COL],int row,int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS],int row,int col);
int GetMineCount(char mine[ROWS][COLS], int x, int y);







#endif //__GAME_H__

 源文件game.c

#define _CRT_SECURE_NO_WARNINGS 1
#include "game.h"

void InitBoard(char a[ROWS][COLS], int rows, int cols,char set)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			a[i][j] = set;
		}
	}

}

void DisplayBoard(char a[ROWS][COLS], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i <= col; i++)
	{
		printf("%d ", i);
	}
	printf("\n");
	for (i = 1; i <= row; i++)
	{
		printf("%d ", i);
		for (j = 1; j <= col; j++)
		{
			printf("%c ", a[i][j]);
		}
		printf("\n");
	}
	printf("\n");
	printf("---------------------------\n");
	printf("\n");

}

void SetMine(char a[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		int x = rand() % ROW+ 1;
		int y = rand() % COL+ 1;
		if (a[x][y] == '0')
		{
			a[x][y] = '1';
			count--;
		}
	}

}

int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
	return mine[x - 1][y] +
		mine[x - 1][y - 1] +
		mine[x][y - 1] +
		mine[x -1][y +1] +
		mine[x + 1][y] +
		mine[x + 1][y+1] +
		mine[x][y + 1] +
		mine[x +1][y-1] - 8 * '0';

}
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win<row*col-EASY_COUNT)
	{
		printf("请输入要排查的坐标：");
		scanf("%d%d", &x, &y);
		if (x >= 1 && x <= row&&y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("很遗憾，你被炸死了！\n");
				DisplayBoard(mine, ROW, COL);
				break;
			}
			else
			{
				int count =GetMineCount(mine,x,y);
				win++;
				show [x][y] = count + '0';
				DisplayBoard(show, ROW, COL);


			}
		}
		else
		{
			printf("坐标非法！请重新输入：\n");
			
		}
	}
	if (win==row*col - EASY_COUNT)
	{
		printf("恭喜你，排雷成功！\n");
		DisplayBoard(mine, ROW, COL);
	}
}

源文件test.c 

#define _CRT_SECURE_NO_WARNINGS 1

#include "game.h"


void menu()
{
	printf("~~~~~~~~~~~~~~~~~~~~~~\n");
	printf("**********************\n");
	printf("****    1.Play    ****\n");
	printf("****    0.Exit    ****\n");
	printf("**********************\n");
	printf("~~~~~~~~~~~~~~~~~~~~~~\n");
}


void game()
{
	//1.布置雷
	char mine[ROWS][COLS] = { 0 };
	char show[ROWS][COLS] = { 0 };
	InitBoard(mine, ROWS, COLS,'0');
	InitBoard(show, ROWS, COLS,'*');
	SetMine(mine, ROW, COL);
	//DisplayBoard(mine,ROW, COL);
	DisplayBoard(show, ROW, COL);
	//2.扫雷
	FindMine(mine,show,ROW,COL);
}

void test()
{
	int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
		menu();
		printf("\n");
		printf("请选择---->");
		scanf("%d", &input);
		printf("\n");
		switch (input)
		{
		case 1:
			game();
			break;
		case 2:
			printf("退出游戏\n");
			break;
		default:
			printf("选择错误，请重新输入\n");
			break;
		}
	} while (input);
}

int main()
{
	test();
	system("pause");
	return 0;
}

写好后来玩一下试试。

游戏界面如下： 

 

这样一步步的玩就ok了！