Codeforces Round #663 (Div. 2) B. Fix You
程序员文章站
2022-04-06 20:07:04
题目链接思路:将每一行最后一个变成D,最后一行全部变成R即可。代码:#include#define int long long#define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);const int N=1e5+3;const int M=2e4+5;const double eps=1e-8;const int mod=998244353;const int inf=0x...
题目链接
思路:
将每一行最后一个变成D,最后一行全部变成R即可。
代码:
#include<bits/stdc++.h> #define int long long #define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); const int N=1e5+3; const int M=2e4+5; const double eps=1e-8; const int mod=998244353; const int inf=0x7fffffff; const double pi=3.1415926; using namespace std; signed main() { IOS; int t; cin >> t; while(t--) { int x=0,y=1; int n,m,sum = 0; cin >> n >> m; char str[n+5][m+5]; for(int i = 1;i <= n;i++) for(int j = 1;j <= m;j++) cin >> str[i][j]; for(int i = 1;i <= n-1;i++) if(str[i][m] == 'R') str[i][m] = 'D',sum++; for(int i = 1;i < m;i++) if(str[n][i] == 'D') str[n][i] = 'R',sum++; cout << sum << endl; } return 0; }
本文地址:https://blog.csdn.net/ACkingdom/article/details/107903531
推荐阅读
-
Codeforces Round #649 (Div. 2)-B. Most socially-distanced subsequence(思维)
-
Codeforces Round #461 (Div. 2) B. Magic Forest(异或的性质)
-
Codeforces Round #654 (Div. 2)-C. A Cookie for You
-
Codeforces Round #663 (Div. 2) B. Fix You
-
Codeforces Round #658 (Div. 2) B. Sequential Nim
-
B. Power Sequence(数学+枚举)Codeforces Round #666 (Div. 2)
-
Codeforces Round #666 (Div. 2)B. Power Sequence(等比数列)
-
Codeforces Round #664 (Div. 2) B. Boboniu Plays Chess
-
Codeforces Round #272 (Div. 2) B. Dreamoon and WiFi (超几何
-
Codeforces Round #258 (Div. 2) B. Sort the Array (模拟)