欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页

直角坐标系点的旋转

程序员文章站 2022-04-04 16:03:22
...

借鉴了此篇文章:https://www.cnblogs.com/orange1438/p/4583825.html,但做了小小的改动,原文是逆时针旋转,我实际

需要方位角的旋转是顺时针,所以小作改动。代码如下:

 * @author xue
 *
 */
public class rotatePoint {
	/**
	 * @param p
	 * @param RotAng
	 * @return
	 */
	private point rotatePointUtil(point p,double RotAng) {
		double RotAngF=360-RotAng;
		RotAngF = (RotAngF * Math.PI / 180d);
        double SinVal = (Math.sin(RotAngF));
        double CosVal = (Math.cos(RotAngF));
        double Nx = (p.x * CosVal - p.y * SinVal);
        double Ny = (p.y * CosVal + p.x * SinVal);
        return new point(Nx, Ny);
	}
	
	public static void main(String[] args) {
		/**
		 * 测试
		 */
		point pt=new point(0,10);
		point ptNew;
		double RotAng=30;
	
		rotatePoint rotUtil=new rotatePoint();
		ptNew=rotUtil.rotatePointUtil(pt, RotAng);
		
		System.out.println(ptNew.toString());
	}
}

其中point类如下:

package cn.xue.Algorithm;
public class point {
	public double x;
	public double y;
	public double getX() {
		return x;
	}
	public void setX(double x) {
		this.x = x;
	}
	public double getY() {
		return y;
	}
	public void setY(double y) {
		this.y = y;
	}
	public point(double x, double y) {
		super();
		this.x = x;
		this.y = y;
	}
	@Override
	public String toString() {
		return "point [x=" + x + ", y=" + y + "]";
	}
	
}

相关标签: Algorithm