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Vicious Keyboard

程序员文章站 2022-04-02 21:27:01
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 Vicious Keyboard

 CodeForces - 801A 

Tonio has a keyboard with only two letters, "V" and "K".

One day, he has typed out a string s with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maximum number of times "VK" can appear as a substring (i. e. a letter "K" right after a letter "V") in the resulting string.

Input

The first line will contain a string s consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100.

Output

Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character.

Examples

Input

VK

Output

1

Input

VV

Output

1

Input

V

Output

0

Input

VKKKKKKKKKVVVVVVVVVK

Output

3

Input

KVKV

Output

1

Note

For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.

For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.

For the fourth case, we can change the fourth character from a "K" to a "V". This will give us the string "VKKVKKKKKKVVVVVVVVVK". This has three occurrences of the string "VK" as a substring. We can check no other moves can give us strictly more occurrences.

题目大意:在只能修改一次的情况下能得到的最多的“VK”数

AC代码

#include <cstdio>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <cstdlib>
#include <cstring>
#include <map>
#include <stack>
#include <queue>
#include <vector>
#include <bitset>
#include <set>
#include <utility>
using namespace std;
typedef long long ll;
#define inf 0x3f3f3f3f
#define rep(i,l,r) for(int i=l;i<=r;i++)
#define lep(i,l,r) for(int i=l;i>=r;i--)
#define ms(arr) memset(arr,0,sizeof(arr))
//priority_queue<int,vector<int> ,greater<int> >q;
const int maxn = (int)1e5 + 5;
const ll mod = 1e9+7;
char str[maxn];
bool vis[maxn];
int main() 
{
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
    ios::sync_with_stdio(0),cin.tie(0);
    scanf("%s",str);
    int len=strlen(str);
    int num=0;
    bool j=false;
   	for(int i=0;i<len-1;i++)
   	{
   		if(str[i]=='V'&&str[i+1]=='K')
    	{
    		num++;
    		vis[i]=true;
    		vis[i+1]=true;
    	}
   	}
    for(int i=0;i<len-1;i++)
    {
    	if((str[i]=='V'&&str[i+1]=='V')||(str[i]=='K'&&str[i+1]=='K'))
    	{
    		if(vis[i]==false&&vis[i+1]==false)
    			j=true;
    	}
    	
    }
    if(j)
    	num++;
    printf("%d\n",num);
    return 0;
}

 

相关标签: 数学