4.3编程实现id3
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2022-03-31 08:08:32
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# -*- coding: utf-8 -*
'''''
create on 2017/3/24, the day after our national football team beat south korea
@author: PY131
'''''
'''
definition of decision node class
attr: attribution as parent for a new branching
attr_down: dict: {key, value}
key: categoric: categoric attr_value
continuous: '<= div_value' for small part
'> div_value' for big part
value: children (Node class)
label: class label (the majority of current sample labels)
'''
import os
os.environ["PATH"] += os.pathsep + 'D:/python(ruanjian)/Graphviz/bin/'
class Node(object):
def __init__(self, attr_init=None, label_init=None, attr_down_init={}):
self.attr = attr_init
self.label = label_init
self.attr_down = attr_down_init
'''
Branching for decision tree using recursion
@param df: the pandas dataframe of the data_set
@return root: Node, the root node of decision tree
'''
def TreeGenerate(df):
# generating a new root node
new_node = Node(None, None, {})
label_arr = df[df.columns[-1]]
label_count = NodeLabel(label_arr)
if label_count: # assert the label_count isn's empty
new_node.label = max(label_count, key=label_count.get)
# end if there is only 1 class in current node data
# end if attribution array is empty
if len(label_count) == 1 or len(label_arr) == 0:
return new_node
# get the optimal attribution for a new branching
new_node.attr, div_value = OptAttr(df)
# recursion
if div_value == 0: # categoric variable
value_count = ValueCount(df[new_node.attr])
for value in value_count:
df_v = df[df[new_node.attr].isin([value])] # get sub set
# delete current attribution
df_v = df_v.drop(new_node.attr, 1)
new_node.attr_down[value] = TreeGenerate(df_v)
else: # continuous variable # left and right child
value_l = "<=%.3f" % div_value
value_r = ">%.3f" % div_value
df_v_l = df[df[new_node.attr] <= div_value] # get sub set
df_v_r = df[df[new_node.attr] > div_value]
new_node.attr_down[value_l] = TreeGenerate(df_v_l)
new_node.attr_down[value_r] = TreeGenerate(df_v_r)
return new_node
'''
make a predict based on root
@param root: Node, root Node of the decision tree
@param df_sample: dataframe, a sample line
'''
def Predict(root, df_sample):
try:
import re # using Regular Expression to get the number in string
except ImportError:
print("module re not found")
while root.attr != None:
# continuous variable
if df_sample[root.attr].dtype == float:
# get the div_value from root.attr_down
for key in list(root.attr_down):
num = re.findall(r"\d+\.?\d*", key)
div_value = float(num[0])
break
if df_sample[root.attr].values[0] <= div_value:
key = "<=%.3f" % div_value
root = root.attr_down[key]
else:
key = ">%.3f" % div_value
root = root.attr_down[key]
# categoric variable
else:
key = df_sample[root.attr].values[0]
# check whether the attr_value in the child branch
if key in root.attr_down:
root = root.attr_down[key]
else:
break
return root.label
'''
calculating the appeared label and it's counts
@param label_arr: data array for class labels
@return label_count: dict, the appeared label and it's counts
'''
def NodeLabel(label_arr):
label_count = {} # store count of label
for label in label_arr:
if label in label_count:
label_count[label] += 1
else:
label_count[label] = 1
return label_count
'''
calculating the appeared value for categoric attribute and it's counts
@param data_arr: data array for an attribute
@return value_count: dict, the appeared value and it's counts
'''
def ValueCount(data_arr):
value_count = {} # store count of value
for label in data_arr:
if label in value_count:
value_count[label] += 1
else:
value_count[label] = 1
return value_count
'''
find the optimal attributes of current data_set
@param df: the pandas dataframe of the data_set
@return opt_attr: the optimal attribution for branch
@return div_value: for discrete variable value = 0
for continuous variable value = t for bisection divide value
'''
def OptAttr(df):
info_gain = 0
for attr_id in df.columns[1:-1]:
info_gian_tmp, div_value_tmp = InfoGain(df, attr_id)
if info_gian_tmp > info_gain:
info_gain = info_gian_tmp
opt_attr = attr_id
div_value = div_value_tmp
return opt_attr, div_value
'''
calculating the information gain of an attribution
@param df: dataframe, the pandas dataframe of the data_set
@param attr_id: the target attribution in df
@return info_gain: the information gain of current attribution
@return div_value: for discrete variable, value = 0
for continuous variable, value = t (the division value)
'''
def InfoGain(df, index):
info_gain = InfoEnt(df.values[:, -1]) # info_gain for the whole label
div_value = 0 # div_value for continuous attribute
n = len(df[index]) # the number of sample
# 1.for continuous variable using method of bisection
if df[index].dtype == float:
sub_info_ent = {} # store the div_value (div) and it's subset entropy
df = df.sort_values([index], ascending=1) # sorting via column
df = df.reset_index(drop=True)
data_arr = df[index]
label_arr = df[df.columns[-1]]
for i in range(n - 1):
div = (data_arr[i] + data_arr[i + 1]) / 2
sub_info_ent[div] = ((i + 1) * InfoEnt(label_arr[0:i + 1]) / n) \
+ ((n - i - 1) * InfoEnt(label_arr[i + 1:-1]) / n)
# our goal is to get the min subset entropy sum and it's divide value
div_value, sub_info_ent_max = min(sub_info_ent.items(), key=lambda x: x[1])
info_gain -= sub_info_ent_max
# 2.for discrete variable (categoric variable)
else:
data_arr = df[index]
label_arr = df[df.columns[-1]]
value_count = ValueCount(data_arr)
for key in value_count:
key_label_arr = label_arr[data_arr == key]
info_gain -= value_count[key] * InfoEnt(key_label_arr) / n
return info_gain, div_value
'''
calculating the information entropy of an attribution
@param label_arr: ndarray, class label array of data_arr
@return ent: the information entropy of current attribution
'''
def InfoEnt(label_arr):
try:
from math import log2
except ImportError:
print("module math.log2 not found")
ent = 0
n = len(label_arr)
label_count = NodeLabel(label_arr)
for key in label_count:
ent -= (label_count[key] / n) * log2(label_count[key] / n)
return ent
def DrawPNG(root, out_file):
'''
visualization of decision tree from root.
@param root: Node, the root node for tree.
@param out_file: str, name and path of output file
'''
try:
from pydotplus import graphviz
except ImportError:
print("module pydotplus.graphviz not found")
g = graphviz.Dot() # generation of new dot
TreeToGraph(0, g, root)
g2 = graphviz.graph_from_dot_data(g.to_string())
g2.write_png(out_file)
def TreeToGraph(i, g, root):
'''
build a graph from root on
@param i: node number in this tree
@param g: pydotplus.graphviz.Dot() object
@param root: the root node
@return i: node number after modified
# @return g: pydotplus.graphviz.Dot() object after modified
@return g_node: the current root node in graphviz
'''
try:
from pydotplus import graphviz
except ImportError:
print("module pydotplus.graphviz not found")
if root.attr == None:
g_node_label = "Node:%d\n好瓜:%s" % (i, root.label)
else:
g_node_label = "Node:%d\n好瓜:%s\n属性:%s" % (i, root.label, root.attr)
g_node = i
g.add_node(graphviz.Node(g_node, label=g_node_label, fontname="FangSong"))
for value in list(root.attr_down):
i, g_child = TreeToGraph(i + 1, g, root.attr_down[value])
g.add_edge(graphviz.Edge(g_node, g_child, label=value, fontname="FangSong"))
return i, g_node
# -*- coding: utf-8 -*
'''''
create on 2017/3/24, the day after our national football team beat south korea
@author: PY131
'''''
'''
import data and pre-analysis through data visualization
'''
# using pandas dataframe for .csv read which contains chinese char.
import pandas as pd
data_file_encode = "gb18030" # the watermelon_3.csv is file codec type
with open("../data/watermelon_3.csv", mode='r', encoding=data_file_encode) as data_file:
df = pd.read_csv(data_file)
# using seaborn for data visualization.
# # load chinese font
# import matplotlib as mpl
# import matplotlib.pyplot as plt
# import seaborn as sns
# # sns.set(style="whitegrid", color_codes=True)
# mpl.rcParams['font.sans-serif'] = ['Droid Sans Fallback'] # for chinese chararter visualization
# mpl.rcParams['axes.unicode_minus'] = False
# sns.set_context("poster")
#
# f1 = plt.figure(1)
# sns.FacetGrid(df, hue="好瓜", size=5).map(plt.scatter, "密度", "含糖率").add_legend()
# sns.plt.show()
#
# f2 = plt.figure(2)
# sns.plt.subplot(221)
# sns.swarmplot(x = "纹理", y = '密度', hue = "好瓜", data = df)
# sns.plt.subplot(222)
# sns.swarmplot(x = "敲声", y = '密度', hue = "好瓜", data = df)
# sns.plt.subplot(223)
# sns.swarmplot(x = "色泽", y = '含糖率', hue = "好瓜", data = df)
# sns.plt.subplot(224)
# sns.swarmplot(x = "敲声", y = '含糖率', hue = "好瓜", data = df)
# sns.plt.show()
'''
implementation of ID3
rely on decision_tree.py
'''
import Chapter4.decision_tree4_3 as decision_tree
root = decision_tree.TreeGenerate(df)
# df = df.drop(['密度','含糖率'], 1)
# df = df.drop(['色泽','根蒂','敲声','纹理','脐部','触感'], 1)
accuracy_scores = []
'''
from random import sample
for i in range(10):
train = sample(range(len(df.index)), int(1*len(df.index)/2))
df_train = df.iloc[train]
df_test = df.drop(train)
# generate the tree
root = decision_tree.TreeGenerate(df_train)
# test the accuracy
pred_true = 0
for i in df_test.index:
label = decision_tree.Predict(root, df[df.index == i])
if label == df_test[df_test.columns[-1]][i]:
pred_true += 1
accuracy = pred_true / len(df_test.index)
accuracy_scores.append(accuracy)
'''
# k-folds cross prediction
n = len(df.index)
k = 5
for i in range(k):
m = int(n / k)
test = []
for j in range(i * m, i * m + m):
test.append(j)
df_train = df.drop(test)
df_test = df.iloc[test]
root = decision_tree.TreeGenerate(df_train) # generate the tree
# test the accuracy
pred_true = 0
for i in df_test.index:
label = decision_tree.Predict(root, df[df.index == i])
if label == df_test[df_test.columns[-1]][i]:
pred_true += 1
accuracy = pred_true / len(df_test.index)
accuracy_scores.append(accuracy)
# print the prediction accuracy result
accuracy_sum = 0
print("accuracy: ", end="")
for i in range(k):
print("%.3f " % accuracy_scores[i], end="")
accuracy_sum += accuracy_scores[i]
print("\naverage accuracy: %.3f" % (accuracy_sum / k))
# dicision tree visualization using pydotplus.graphviz
root = decision_tree.TreeGenerate(df)
decision_tree.DrawPNG(root, "decision_tree_ID3.png")
参考网址:
https://blog.csdn.net/snoopy_yuan/article/details/68959025
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