java中关于BigDecimal用法的思考
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2022-03-30 17:10:14
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public static void main(String[] args) {
double num1 = 30.0000000000000003;
System.out.println(num1 == 30);
BigDecimal bigNum1 = new BigDecimal(new Double(num1).toString());
BigDecimal bigNum2 = new BigDecimal(new Double(num1));
System.out.println(bigNum1.equals(30));
System.out.println(bigNum2.equals(30));
System.out.println("-----------------------------");
// BigDecimal的构造函数 public BigDecimal(double val) 损失了double 参数的精度
// 一些资料中提到使用字符串来构建BigDecimal更加精确,通过以下示例发现确实有效
double d = 301353.05;
BigDecimal bigNum3 = new BigDecimal(d);
System.out.println(bigNum3);//301353.0499999999883584678173065185546875
BigDecimal bigNum4 = new BigDecimal(new Double(d).toString());
System.out.println(bigNum4);
// System.out.println(decimal.setScale(1, RoundingMode.HALF_UP));//301353.0
System.out.println("-----------------------------");
// 然而Double的toString()方法并不是一个精确的方法
// 其输出的字符串为一个接近的值
d = 301353.0499999999883584678173065185546875d;
System.out.println(d);
System.out.println(new Double(d).toString());
System.out.println(new Double(d).toString());
System.out.println(new BigDecimal(d));
}
输出:
true
false
false
-----------------------------
301353.0499999999883584678173065185546875
301353.05
-----------------------------
301353.05
301353.05
301353.05
301353.0499999999883584678173065185546875
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