[LeetCode]38. Count and Say

题目描述

思路

字符串拼接，暴力遍历即可

代码

#include <iostream>
#include <string>

using namespace std;

class Solution {
public:
    string countAndSay(int n) {
        if (n == 0)
            return "";
        string res = "1";
        while (--n) {
            string cur = "";
            for (int i = 0; i < res.size(); ++i) {
                int count = 1;
                while (i + 1 < res.size() && res[i] == res[i + 1]) {
                    ++count;
                    ++i;
                }
                cur += to_string(count) + res[i];
            }
            res = cur;
        }
        return res;
    }
};

int main() {
    Solution s;
    cout << s.countAndSay(5) << endl;

    system("pause");
    return 0;
}