C++ 获取时间戳并转换时间

#include<iostream>
#include<ctime>
using namespace std;
int main()
{
 time_t curtime;
 curtime = time(NULL);
 cout<<curtime<<endl;

 char temp[100];
 curtime += 28800;
 struct tm *timeSet = gmtime(&curtime);
 strftime(temp,50, "%Y-%m-%d %H:%M:%S", timeSet);
 cout << temp << endl;
 return 0;
}