动态规划求字符串的公共最长子序列的长度算法
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2024-02-26 15:35:16
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动态规划求字符串的公共最长子序列的长度算法
public class LongestCommonSubsequence {
int lcs(char[] X, char[] Y, int m, int n) {
int L[][] = new int[m + 1][n + 1];
for (int i = 0; i <= m; i++) {
for (int j = 0; j <= n; j++) {
if (i == 0 || j == 0)
L[i][j] = 0;
else if (X[i - 1] == Y[j - 1])
L[i][j] = L[i - 1][j - 1] + 1;
else
L[i][j] = max(L[i - 1][j], L[i][j - 1]);
}
}
return L[m][n];
}
int max(int a, int b) {
return (a > b) ? a : b;
}
public static void main(String[] args) {
LongestCommonSubsequence lcs = new LongestCommonSubsequence();
Scanner input = new Scanner(System.in);
System.out.println("Please enter string-1:");
String s1 = input.next();
System.out.println("Please enter string-2:");
String s2 = input.next();
char[] X = s1.toCharArray();
char[] Y = s2.toCharArray();
int m = X.length;
int n = Y.length;
System.out.println("Result:");
System.out.println(" 公共最长子序列为" + " " + lcs.lcs(X, Y, m, n));
}
}
运行结果
Please enter string-1:
ewrqreqw
Please enter string-2:
qwrwqrte
Result:
公共最长子序列为 5