！php+ajax+ json 有关问题

程序员文章站 2024-01-14 11:18:40

...

求助！！php+ajax+ json 问题

本帖最后由 zl2727 于 2013-12-10 18:08:23 编辑


function gtou($s) { return iconv('gbk', 'utf-8', $s); }
$proquery ="select * from pro where typeid='".$id."' order by corank asc";
 $dsql->SetQuery($proquery); 
$dsql->Execute(); 
$a=array();
 while($row = $dsql->GetArray())
 {
 $a[]= array_map('gtou', $row); 
} 
$res = array(
 "status" => "1",
 "result" => $a,
 "moreUrl" => $moreurl, );
 echo json_encode($res);

现在前台返回值是{"status":"1","result":[],"moreUrl":"http:\/\/wcn"} result 是空的
如果
echo json_encode($res);
换成下面的
//echo '{"status":"1","result":[{"id":"1","typeid":"111","goodstitle":"\u8865\u6c34\u6da6\u80a4\u818f \u771f\u7684\u5f88\u597d \u5f88\u8865\u6c34 \u76ae\u80a4\u6709\u5f39\u6027","goodsurl":"http:\/\/www.\/uploads\/allimg\/c131205\/13V23912150-114L_lit.jpg","brandtitle":"\u7f8e\u5b9d\u83b2","brandurl":"http:\/\/www.\/dsadasdas\/","imgurl":"http:\/\/www.\/sadas213\/","price":"59.9","corank":"1"},{"id":"2","typeid":"111","goodstitle":"\u8865\u6c34\u6da6\u80a4222","goodsurl":"http:\/\/www.\/uploads\/allimg\/c131205\/13V23912150-114L_lit.jpg","brandtitle":"\u7f8e222","brandurl":"http:\/\/www.\/dsadasdas\/","imgurl":"http:\/\/www.\/sadas213\/","price":"59.9","corank":"1"}],"moreUrl":"http:\/\/jianfei.\/shuiguo\/"}'; 就正确了请大神们帮个忙版主也麻烦您再次指导以下