Python新手实现2048小游戏

接触 python 不久，看到很多人写2048，自己也捣鼓了一个，主要是熟悉python语法。

程序使用python3 写的，代码150行左右，基于控制台，方向键使用输入字符模拟。

演示图片

2048.py

# -*- coding:utf-8 -*-
#! /usr/bin/python3
 
import random
 
v = [[0, 0, 0, 0],
   [0, 0, 0, 0],
   [0, 0, 0, 0],
   [0, 0, 0, 0]]
 
def display(v, score):
    '''显示界面
 
    '''
    print('{0:4} {1:4} {2:4} {3:4}'.format(v[0][0], v[0][1], v[0][2], v[0][3]))
    print('{0:4} {1:4} {2:4} {3:4}'.format(v[1][0], v[1][1], v[1][2], v[1][3]))
    print('{0:4} {1:4} {2:4} {3:4}'.format(v[2][0], v[2][1], v[2][2], v[2][3]))
    print('{0:4} {1:4} {2:4} {3:4}'.format(v[3][0], v[3][1], v[3][2], v[3][3]), '  total score: ', score)
 
def init(v):
    '''随机分布网格值
     
    '''
    for i in range(4):
        v[i] = [random.choice([0, 0, 0, 2, 2, 4]) for x in range(4)]
 
def align(vlist, direction):
    '''对齐非零的数字
 
    direction == 'left'：向左对齐，例如[8,0,0,2]左对齐后[8,2,0,0]
    direction == 'right'：向右对齐，例如[8,0,0,2]右对齐后[0,0,8,2]
    '''
 
    # 移除列表中的0
    for i in range(vlist.count(0)):
        vlist.remove(0)
    # 被移除的0
    zeros = [0 for x in range(4 - len(vlist))]
    # 在非0数字的一侧补充0
    if direction == 'left':
        vlist.extend(zeros)
    else:
        vlist[:0] = zeros
     
def addsame(vlist, direction):
    '''在列表查找相同且相邻的数字相加, 找到符合条件的返回true，否则返回false,同时还返回增加的分数
     
    direction == 'left':从右向左查找，找到相同且相邻的两个数字，左侧数字翻倍，右侧数字置0
    direction == 'right':从左向右查找，找到相同且相邻的两个数字，右侧数字翻倍，左侧数字置0
    '''
    score = 0
    if direction == 'left':
        for i in [0, 1, 2]:
            if vlist[i] == vlist[i+1] != 0: 
                vlist[i] *= 2
                vlist[i+1] = 0
                score += vlist[i]
                return {'bool':true, 'score':score}
    else:
        for i in [3, 2, 1]:
            if vlist[i] == vlist[i-1] != 0:
                vlist[i-1] *= 2
                vlist[i] = 0
                score += vlist[i-1]
                return {'bool':true, 'score':score}
    return {'bool':false, 'score':score}
 
def handle(vlist, direction):
    '''处理一行（列）中的数据，得到最终的该行（列）的数字状态值, 返回得分
 
    vlist: 列表结构，存储了一行（列）中的数据
    direction: 移动方向,向上和向左都使用方向'left'，向右和向下都使用'right'
    '''
    totalscore = 0
    align(vlist, direction)
    result = addsame(vlist, direction)
    while result['bool'] == true:
        totalscore += result['score']
        align(vlist, direction)
        result = addsame(vlist, direction)
    return totalscore
     
 
def operation(v):
    '''根据移动方向重新计算矩阵状态值，并记录得分
    '''
    totalscore = 0
    gameover = false
    direction = 'left'
    op = input('operator:')
    if op in ['a', 'a']:  # 向左移动
        direction = 'left'
        for row in range(4):
            totalscore += handle(v[row], direction)
    elif op in ['d', 'd']: # 向右移动
        direction = 'right'
        for row in range(4):
            totalscore += handle(v[row], direction)
    elif op in ['w', 'w']: # 向上移动
        direction = 'left'
        for col in range(4):
            # 将矩阵中一列复制到一个列表中然后处理
            vlist = [v[row][col] for row in range(4)]
            totalscore += handle(vlist, direction)
            # 从处理后的列表中的数字覆盖原来矩阵中的值
            for row in range(4):
                v[row][col] = vlist[row]
    elif op in ['s', 's']: # 向下移动
        direction = 'right'
        for col in range(4):
            # 同上
            vlist = [v[row][col] for row in range(4)]
            totalscore += handle(vlist, direction)
            for row in range(4):
                v[row][col] = vlist[row]
    else:
        print('invalid input, please enter a charactor in [w, s, a, d] or the lower')
        return {'gameover':gameover, 'score':totalscore}
 
    # 统计空白区域数目 n
    n = 0
    for q in v:
      n += q.count(0)
    # 不存在剩余的空白区域时，游戏结束
    if n == 0:
        gameover = true
        return {'gameover':gameover, 'score':totalscore}
 
    # 按2和4出现的几率为3/1来产生随机数2和4
    num = random.choice([2, 2, 2, 4]) 
    # 产生随机数k，上一步产生的2或4将被填到第k个空白区域
    k = random.randrange(1, n+1)
    n = 0
    for i in range(4):
        for j in range(4):
            if v[i][j] == 0:
                n += 1
                if n == k:
                    v[i][j] = num
                    break
 
    return {'gameover':gameover, 'score':totalscore}
 
init(v)
score = 0
print('input：w(up) s(down) a(left) d(right), press <cr>.')
while true:
    display(v, score)
    result = operation(v)
    if result['gameover'] == true:
        print('game over, you failed!')
        print('your total score:', score)
    else:
        score += result['score']
        if score >= 2048:
            print('game over, you win!!!')
            print('your total score:', score)

以上所述就是本文给大家分享的全部代码了，希望能够对大家学习python有所帮助。