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常用的排序算法二(归并排序)

程序员文章站 2022-03-02 08:14:11
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归并排序

将数组分为左右两部分
将左右部分分别排好序(递归见代码sortProcess函数)
建立辅助数组,将左右两边排好序的子数组按照大小放入辅助数组里,然后将辅助数组拷贝到原数组中。见代码merge函数

#include <iostream>
#include <vector>
using namespace std;

class Solution {
public:
    // 归并排序
    /*
     * 1. 将数组分为左右两部分,左右边分别排好序
     * 2. 建立辅助数组,将左右两边排好序的子数组按照大小放入辅助数组里
     * 3. 将辅助数组拷贝到原数组中
     * */
    void merge(vector<int>& example, int left, int mid, int right) {
        vector<int> tmp;
        int p1 = left, p2 = mid + 1;
        while (p1 <= mid && p2 <= right) {
            if (example[p1] < example[p2]) {
                tmp.push_back(example[p1]);
                p1++;
            } else {
                tmp.push_back(example[p2]);
                p2++;
            }
        }
        while (p1 <= mid) {
            for (int i = p1; i <= mid; i++) {
                tmp.push_back(example[i]);
                p1++;
            }
        }
        while (p2 <= right) {
            for (int i = p2; i <= right; i++) {
                tmp.push_back(example[i]);
                p2++;
            }
        }
        for (int i = 0; i < tmp.size(); i++) {
            example[left+i] = tmp[i];
        }
    }
    void sortProcess(vector<int>& example, int left, int right) {
        if (left == right) {
            return;
        }
        int mid = left + ((right - left) >> 1);
        sortProcess(example, left, mid);
        sortProcess(example, mid + 1, right);
        merge(example, left, mid, right);
    }
    void mergeSort(vector<int>& example) {
        if (example.empty() || example.size() == 1) {
            return;
        }
        sortProcess(example, 0, example.size() - 1);
    }
};

int main()
{
    vector<int> example = {1, 12, 9, 3, 6};
    cout << "排序前的数组为: ";
    for (int i = 0; i < example.size() - 1; i++) {
        cout << example[i] << ", ";
    }
    cout << example[example.size()-1] << endl;
    cout << "----------------------------" << endl;
    Solution su;
    su.mergeSort(example);
    cout << "排序后的数组为: ";
    for (int i = 0; i < example.size() - 1; i++) {
        cout << example[i] << ", ";
    }
    cout << example[example.size()-1] << endl;
    return 0;
}