Newtonsoft.Json.Linq 常用方法总结
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2022-08-08 15:44:51
[TOC] 1、Entity to Json 1.1、准备工作 我们以如下的 类举例,其中包含了常用的数据类型: 创建一个 实例: 1.2、Entity to Json 返回不缩进的 Json 字符串 返回: 返回缩进的 Json 字符串 返回: Json 字符串缩进 或者: 其他设置 返回: 1. ......
目录
1、entity to json
1.1、准备工作
我们以如下的 person
类举例,其中包含了常用的数据类型:
public class person { public int id { get; set; } public string name { get; set; } public datetime birthday { get; set; } public bool isvip { get; set; } public float account { get; set; } public string[] favorites { get; set; } public string remark { get; set; } }
创建一个 person
实例:
person person = new person { id = 1, name = "张三", birthday = datetime.parse("2000-01-02"), isvip = true, account = 12.34f, favorites = new string[] { "吃饭", "睡觉" } };
1.2、entity to json
返回不缩进的 json 字符串
jsonconvert.serializeobject(person)
返回:
{"id":1,"name":"张三","birthday":"2000-01-02t00:00:00","isvip":true,"account":12.34,"favorites":["吃饭","睡觉"],"remark":null}
返回缩进的 json 字符串
jsonconvert.serializeobject(person, formatting.indented);
返回:
{ "id": 1, "name": "张三", "birthday": "2000-01-02t00:00:00", "isvip": true, "account": 12.34, "favorites": [ "吃饭", "睡觉" ], "remark": null }
json 字符串缩进
private string jsonindentation(string str) { //string str = jsonconvert.serializeobject(entity); jsonserializer serializer = new jsonserializer(); textreader tr = new stringreader(str); jsontextreader jtr = new jsontextreader(tr); object obj = serializer.deserialize(jtr); if (obj != null) { stringwriter textwriter = new stringwriter(); jsontextwriter jsonwriter = new jsontextwriter(textwriter) { formatting = formatting.indented, indentation = 4, indentchar = ' ' }; serializer.serialize(jsonwriter, obj); return textwriter.tostring(); } else { return str; } }
或者:
private string jsonindentation(string json) { jobject obj = jobject.parse(json); return obj.tostring(); }
其他设置
jsonserializersettings settings = new jsonserializersettings(); // 设置日期格式 settings.dateformatstring = "yyyy-mm-dd"; // 忽略空值 settings.nullvaluehandling = nullvaluehandling.ignore; // 缩进 settings.formatting = formatting.indented; jsonconvert.serializeobject(person, settings);
返回:
{ "id": 1, "name": "张三", "birthday": "2000-01-02", "isvip": true, "account": 12.34, "favorites": [ "吃饭", "睡觉" ] }
1.3、json to entity
jsonconvert.deserializeobject<person>(json);
2、linq to json
2.1、创建对象
jobject obj = new jobject(); obj.add("id", 1); obj.add("name", "张三"); obj.add("birthday", datetime.parse("2000-01-02")); obj.add("isvip", true); obj.add("account", 12.34f); // 创建数组 jarray array = new jarray(); array.add(new jvalue("吃饭")); array.add(new jvalue("睡觉")); obj.add("favorites", array); obj.add("remark", null);
2.2、从 json 字符串创建 jobject
string json = "{\"id\":1,\"name\":\"张三\",\"birthday\":\"2000-01-02t00:00:00\",\"isvip\":true,\"account\":12.34,\"favorites\":[\"吃饭\",\"睡觉\"],\"remark\":null}"; jobject obj = jobject.parse(json);
2.3、从 entity 创建 jobject
jobject obj = jobject.fromobject(person);
用匿名对象创建 jobject
jobject obj = jobject.fromobject(new { name = "jack", age = 18 });
显示:
{ "name": "jack", "age": 18 }
2.2、获取值
int id; if (obj["id"] != null) id = obj["id"].value<int>();
获取数组
newtonsoft.json.linq 不支持直接获取数组,但是可以获取 list
,然后再转化为数组。
string[] favorites; if (obj["favorites"] != null) favorites = obj["favorites"].value<list<string>>().toarray();
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