GWT-response could not be deserializedcom
程序员文章站
2022-07-16 16:33:57
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response could not be deserializedcom.google.gwt.user.client.rpc.SerializationException: java.sql.Timestamp/1769758459
参考链接:
http://sourceforge.net/tracker/index.php?func=detail&aid=3285026&group_id=239931&atid=1111398
http://groups.google.com/group/google-web-toolkit/browse_thread/thread/6ac416ba4dbae1aa
原因:
Gilead中的一个jar包与GWT冲突
解决方法:
1、用zip工具打开gilead4gwt*.jar这个包,然后移除com.google.gwt.user.client.rpc.core.java.sql下的*.class和*.java
2、要使用gwt-servlet.jar下面的com.google.gwt.user.client.rpc.core.java.sql.*
只要把gwt-servlet.jar的位置放在gilead4gwt*.jar的前面就好
参考链接:
http://sourceforge.net/tracker/index.php?func=detail&aid=3285026&group_id=239931&atid=1111398
http://groups.google.com/group/google-web-toolkit/browse_thread/thread/6ac416ba4dbae1aa
原因:
Gilead中的一个jar包与GWT冲突
解决方法:
1、用zip工具打开gilead4gwt*.jar这个包,然后移除com.google.gwt.user.client.rpc.core.java.sql下的*.class和*.java
2、要使用gwt-servlet.jar下面的com.google.gwt.user.client.rpc.core.java.sql.*
只要把gwt-servlet.jar的位置放在gilead4gwt*.jar的前面就好
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