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一段smali代码的分析

程序员文章站 2022-07-15 15:23:10
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java源代码:
  public void payFailed(Map paramMap, int paramInt)
  {
    Log.d("cocos2d-x debug info", "Failed DX_payCode2 == " + IAPListener.DX_PAYCODES[this.this$0.curPayIndex]);
    Log.d("cocos2d-x debug info", "FaildCode == " + paramInt);
    GameJni.OderFinish(this.this$0.curPayIndex, 0);
    IAPListener.iapHandler.sendMessage(Message.obtain(IAPListener.iapHandler, 10005, IAPListener.DX_PAYCODES[this.this$0.curPayIndex]));
  }

对应的smali语句:

.method public payFailed(Ljava/util/Map;I)V
    .locals 5
    .param p1, "params"    # Ljava/util/Map;
    .param p2, "arg1"    # I

    .prologue
    .line 208
    const-string v0, "cocos2d-x debug info"
     #1.new instance
    new-instance v1, Ljava/lang/StringBuilder;
       #2调用构造
    invoke-direct {v1}, Ljava/lang/StringBuilder;-><init>()V
     #对应源代码中的log.d  中的字符串
    const-string v2, "Failed DX_payCode2 == "
        #3.调用append函数
    invoke-virtual {v1, v2}, Ljava/lang/StringBuilder;->append(Ljava/lang/String;)Ljava/lang/StringBuilder;

    move-result-object v1
#获取 DX_PAYCODES对象
    sget-object v2, Lcom/payCom/org/IAPListener;->DX_PAYCODES:[Ljava/lang/String;

    iget-object v3, p0, Lcom/payCom/org/IAPListener$1;->this$0:Lcom/payCom/org/IAPListener;

    iget v3, v3, Lcom/payCom/org/IAPListener;->curPayIndex:I              
      #获取数组v2里面的第v3个元素v2
    aget-object v2, v2, v3
     #调用虚方法v1.append(v2),见书20/73                                        
    invoke-virtual {v1, v2}, Ljava/lang/StringBuilder;->append(Ljava/lang/String;)Ljava/lang/StringBuilder;
      #将上一个invoke类型的指令操作的对象赋值给v1,
#将刚才上面所得到的值放入v1当中
    move-result-object v1

    invoke-virtual {v1}, Ljava/lang/StringBuilder;->toString()Ljava/lang/String;

    move-result-object v1

    invoke-static {v0, v1}, Landroid/util/Log;->d(Ljava/lang/String;Ljava/lang/String;)I

    .line 209
    const-string v0, "cocos2d-x debug info"

    new-instance v1, Ljava/lang/StringBuilder;

    invoke-direct {v1}, Ljava/lang/StringBuilder;-><init>()V

    const-string v2, "FaildCode == "

    invoke-virtual {v1, v2}, Ljava/lang/StringBuilder;->append(Ljava/lang/String;)Ljava/lang/StringBuilder;

    move-result-object v1

    invoke-virtual {v1, p2}, Ljava/lang/StringBuilder;->append(I)Ljava/lang/StringBuilder;

    move-result-object v1

    invoke-virtual {v1}, Ljava/lang/StringBuilder;->toString()Ljava/lang/String;

    move-result-object v1

    invoke-static {v0, v1}, Landroid/util/Log;->d(Ljava/lang/String;Ljava/lang/String;)I

    .line 210
    iget-object v0, p0, Lcom/payCom/org/IAPListener$1;->this$0:Lcom/payCom/org/IAPListener;

    iget v0, v0, Lcom/payCom/org/IAPListener;->curPayIndex:I

    const/4 v1, 0x0

    invoke-static {v0, v1}, Lcom/payCom/org/GameJni;->OderFinish(II)V

    .line 211
    sget-object v0, Lcom/payCom/org/IAPListener;->iapHandler:Lcom/payCom/org/IAPHandler;

    sget-object v1, Lcom/payCom/org/IAPListener;->iapHandler:Lcom/payCom/org/IAPHandler;

    const/16 v2, 0x2715

    sget-object v3, Lcom/payCom/org/IAPListener;->DX_PAYCODES:[Ljava/lang/String;

    iget-object v4, p0, Lcom/payCom/org/IAPListener$1;->this$0:Lcom/payCom/org/IAPListener;

    iget v4, v4, Lcom/payCom/org/IAPListener;->curPayIndex:I

    aget-object v3, v3, v4

    invoke-static {v1, v2, v3}, Landroid/os/Message;->obtain(Landroid/os/Handler;ILjava/lang/Object;)Landroid/os/Message;

    move-result-object v1

    invoke-virtual {v0, v1}, Lcom/payCom/org/IAPHandler;->sendMessage(Landroid/os/Message;)Z

    .line 212
    return-void
.end method

.method public payFailed(Ljava/util/Map;I)V
.method表示这是一个方法,
payFailed为方法名字
(Ljava/util/Map;I)算是函数里面的形参
v为返回值,返回值为空,这里
.locals 5定义局部变量寄存器
.param p1, "params" 声明参数params
这里是p命名方式
.param p2, "arg1"声明参数arg1
.prologue表示函数开始
.end method表示函数结束

const-string v0, "cocos2d-x debug info"定义了一个字符串常量变量
"Failed DX_payCode2 == " + IAPListener.DX_PAYCODES[this.this$0.curPayIndex]:
这里表示"Failed DX_payCode2 == "这个字符串与另外一个字符串合并变成了一个长的字符串,而它"Failed DX_payCode2 == "是需要一个对象来"存“的,所以下面先new出一个对象(实例),然后在调用构造函数;
new-instance v1, Ljava/lang/StringBuilder:new出一个实例;
invoke-direct {v1}, Ljava/lang/StringBuilder;-><init>()V:调用构造;
const-string v2, "Failed DX_payCode2 == "定义字符串,为"Failed DX_payCode2 == " + IAPListener.DX_PAYCODES[this.this$0.curPayIndex]这一步做准备;
invoke-virtual {v1, v2}, Ljava/lang/StringBuilder;->append(Ljava/lang/String;)Ljava/lang/StringBuilder:调用append这个函数,实施"Failed DX_payCode2 == " + IAPListener.DX_PAYCODES[this.this$0.curPayIndex]这一步;
move-result-object v1将刚才所得到的值放入 v1当中;
sget-object v2, Lcom/payCom/org/IAPListener;->DX_PAYCODES:[Ljava/lang/String;获取Lcom/payCom/org/IAPListener这个类当中的对象DX_PAYCODES

iget-object v3, p0, Lcom/payCom/org/IAPListener$1;->this$0:Lcom/payCom/org/IAPListener;调用(获取)对象,其实就是点出this$0(内部类)(即 .this$0)
iget v3, v3, Lcom/payCom/org/IAPListener;->curPayIndex:I 获取索引(整型);
aget-object v2, v2, v3获取数组v2(第二个v2)里面的第v3个元素v2(第一个v2)

invoke-virtual {v1, v2}, Ljava/lang/StringBuilder;->append(Ljava/lang/String;)Ljava/lang/StringBuilder;调用虚方法v1.append(v2),注意,这里的v1里面已经有了"Failed DX_payCode2 == " + IAPListener.DX_PAYCODES[this.this$0.curPayIndex],这里调用append``函数,是想再"加"上v2;
move-result-object v1将所得的值放入v1当中;
invoke-virtual {v1}, Ljava/lang/StringBuilder;->toString()Ljava/lang/String;调用虚函数,得到最后的字符串;

move-result-object v1作用同上;
invoke-static {v0, v1}, Landroid/util/Log;->d(Ljava/lang/String;Ljava/lang/String;)I调用静态方法,v0应该是指函数内的局部变量const-string v0, "cocos2d-x debug info",最后这这个函数相当于Log.d("cocos2d-x debug info", "Failed DX_payCode2 == " + IAPListener.DX_PAYCODES[this.this$0.curPayIndex])