包含小数的二进制十进制转换

import math
num = input("请输入要转换的数")
judge = int(input("次数为二进制数请输1，此数为十进制数请输2:"))
DEC = 0
BIN = float(0)
if judge == 1:
    location = num.find(".")
    for i in range(0, len(num)):
        if i < location:  # 整数运算
            DEC += int(num[location-(i+1)])*pow(2, i)
        if i > location:  # 小数运算
            DEC += int(num[len(num) - (i + 1)]) * pow(2, location - i)
    print(num + "转换为十进制数为：", DEC)
if judge == 2:  # 使用2的二次幂的方法。
    DEC = float(num)
    i = 0
    saveI = []
    saveF = []
    #整数部分
    while DEC >= 2:
        if pow(2, i) > DEC:
            saveI.append(i-1)
            DEC -= pow(2, i-1)
            i = 0
        i += 1
    if int(DEC) > 0:
        saveI.append(0)
    #小数部分
    DEC = float(num)
    DEC = float(DEC) - int(float(num))
    while DEC < 1 and DEC != 0:
        i -= 1
        if pow(2, i) <= DEC:
            saveF.append(i)
            DEC -= pow(2, i)
            i = 0
    for i in range(0, len(saveI)):
        BIN += pow(10, saveI[i])
    for i in range(0, len(saveF)):
        BIN += pow(10, saveF[i])
    print(num, "转换为二进制数为：", BIN)

写作业时顺道写的