crypto

应该是一道凯撒加密的题目

```python
str = 'gmbh{ifmmp_dug}'
for my in range(1,26):



    for i in str:
        mw = ord(i)
        if (64 < mw < 91):
            jm = mw + my
            if jm > 90:
                jm = (mw - 26) + my
                print(chr(jm), end='')
            else:
                print(chr(jm), end='')
        elif (96 < mw < 123):
            jm = mw + my
            if jm > 122:
                jm = (mw - 26) + my
                print(chr(jm), end='')
            else:
                print(chr(jm), end='')
        else:
            jm = mw + 0
            print(chr(jm), end='')
    print("            ")

这是我写的一个脚本