jquery ajax 异步servlet
程序员文章站
2022-07-12 19:19:43
...
ajax的get方式
$.ajax({
type: "Get",
url: "/xiangmu/user/preparPayWeixin/result/"+out_trade_no+".action",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(data) {
if(data.data == 'success'){
}
},
error: function(err) {
}
});
ajax的post方式
$.ajax({
type: "Post",
url: "/xxx/user/preparPayWeixin/result.action",
contentType: "application/json; charset=utf-8",
dataType: "json",
async: true,//是否同步
data:{Name:"sanmao",Password:"sanmaoword"},
success: function(data) {
if(data.data == 'success'){
}
},
error: function(err) {
}
});
servlet端,返回json
HttpServletResponse response= getResponse();
try {
//设置页面不缓存
response.setContentType("application/json");
response.setHeader("Pragma", "No-cache");
response.setHeader("Cache-Control", "no-cache");
response.setCharacterEncoding("UTF-8");
PrintWriter out= null;
out = response.getWriter();
out.print("{\"data\":\"success\"}");
out.flush();
out.close();
} catch (IOException e) {
e.printStackTrace();
}
springmvc端:
get方式:路径参数为sn
@Controller
@RequestMapping("/user/preparPayWeixin")
public class PreparPayNotifyWeixinController extends BaseController{
//路径参数为sn的get方式
@ResponseBody//返回为json
@RequestMapping(value="result/{sn}",produces = "text/html;charset=UTF-8",method = {RequestMethod.POST, RequestMethod.GET})
public String getResult(@PathVariable("sn") String sn){
String re = "{\"data\":\"success\"}";
return re;
}
post方式:java接收
@RequestMapping("culFee")
public @ResponseBody String culFee(Model model,@RequestBody String data){
//@RequestBody,来接收参数
return json形式字符串;
}