找出数组中符合某些条件的对象数组
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2022-07-12 14:14:20
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前言
过滤出符合某些条件的数组
一、当条件为单个时
const data = [
{id: 1,topic: '难过',title: '再见只是陌生人' },
{id: 2,topic: '遗憾',title: '落空'},
{id: 3,topic: '回忆',title: '那女孩对我说' }
]
function filterData(data, params) {
let _data = data.filter(item => item[params] === 2)
return _data
}
console.log(filterData(data, 'id')) //[{id: 2, topic: "遗憾", title: "落空"}]
二、当条件为对象时
const data = [{
topic_id: 1,
topic_name: '侧脸',
first_class_category: '歌曲',
second_class_category: '回忆',
reviewing: 1,
reviewed: 23,
filtered: 111,
effective_date: '2020-12-20 00:06:00',
review_status: 'reviewing',
online_status: 'offline',
owner: '于果',
},
{
topic_id: 2,
topic_name: '小幸运',
first_class_category: '音乐',
second_class_category: '青春',
reviewing: 2,
reviewed: 33,
filtered: 121,
effective_date: '2020-12-20 00:06:00',
review_status: 'filtered',
online_status: 'offline',
owner: '田馥甄',
},
{
topic_id: 3,
topic_name: '光年之外',
first_class_category: '歌曲',
second_class_category: '天籁之音',
reviewing: 3,
reviewed: 53,
filtered: 151,
effective_date: '2020-12-20 00:06:00',
review_status: 'reviewed',
online_status: 'online',
owner: '邓紫棋',
},
]
function filterData(data, obj) {
return data.filter(item => {
return Object.entries(obj).every(([_key, _val]) => {
if (item[_key] === _val) return true
})
})
}
let obj = {
first_class_category: '歌曲',
review_status: 'reviewed'
}
console.log(filterData(data, obj))
//[{effective_date: "2020-12-20 00:06:00",filtered: 151,first_class_category: "歌曲",online_status: "online",owner: "邓紫棋",review_status: "reviewed",reviewed: 53,reviewing: 3,second_class_category: "天籁之音",topic_id: 3,topic_name: "光年之外"}]
总结
Ojbect.entries()返回可枚举属性的键值对数组
例如:
let obj1 = {
id: 1,
topic: '难过',
title: '再见只是陌生人'
}
console.log(Object.entries(obj)) //[["first_class_category", "歌曲"],["review_status", "reviewed"]]
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